passing argument containing space in shell script

问题:

For some reason I need my script to be able to accept arguments with space characters. If for example I have a script as follows,

for SOME_VAR in $@
do
    echo "$SOME_VAR"
    cd "$SOME_VAR"
done;

if I pass arguments to the script (assuming it is called foo.sh)

sh foo.sh "Hello world"

I am expecting the script to print Hello world and change the directory to "Hello world". But I get this error message instead

hello
cd: 5: can't cd to hello
world
cd: 5: can't cd to world

so how exactly do I pass argument with space char to a command in a shell script?!

回答1:

You must wrap the $@ in quotes, too: "$@"

This tells the shell to ignore spaces in the arguments; it doesn't turn all arguments into a very long string.