我正在试图做的是INSERT
在我的数据库用户,但IF EXISTS
应该UPDATE
行, ELSE INSERT INTO
新行。
Ofcourse我连接到数据库第一和GET
在$name
, $email
和$birthday
从URL字符串。
$con=mysqli_connect("localhost","---","---","---");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$name=$_GET['name'];
$email=$_GET['email'];
$birthday=$_GET['birthday'];
这个工作,但只是增加了新的行;
mysqli_query($con,"INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES ('$name', '$email', '$birthday')");
mysqli_close($con);
这是我试过;
mysqli_query($con,"INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES '$name', '$email', '$birthday'
ON DUPLICATE KEY UPDATE subs_name = VALUES($name), subs_birthday = VALUES($birthday)");
mysqli_close($con);
和
mysqli_query($con,"IF EXISTS (SELECT * FROM subs WHERE subs_email='$email')
UPDATE subs SET subs_name='$name', subs_birthday='$birthday' WHERE subs_email='$email'
ELSE
INSERT INTO subs (subs_name, subs_email, subs_birthday) VALUES ('$name', '$email', '$birthday')");
mysqli_close($con);
和
mysqli_query($con,"IF NOT EXISTS(SELECT * FROM subs WHERE subs_email='$email')
Begin
INSERT INTO subs (subs_name, subs_email, subs_birthday)
VALUES ('$name', '$email', '$birthday')
End");
mysqli_close($con);
但他们没有工作,我究竟做错了什么?
任何帮助是极大的赞赏!