找出天仍从日期的阵列[重复](finding out days remain from array

这个问题已经在这里有一个答案：

• 如何使包含数字另一个阵列的剩余天数 3个回答

我有一个数组类似下面

_combinedBirthdates(
"03/12/2013",
"03/12/2013",
"08/13/1990",
"12/09/1989",
"02/06",
"09/08",
"03/02/1990",
"08/22/1989",
"03/02",
"05/13",
"10/16",
"07/08",
"08/31/1990",
"04/14/1992",
"12/15/1905",
"08/14/1989",
"10/07/1987",
"07/25",
"07/17/1989",
"03/24/1987",
"07/28/1988",
"01/21/1990",
"10/13"

）

这一切都是的NSString

我想从这个包含剩余天数类似下面做出新的阵列

（剩余天数为特定的生日）（我们将康普艾当前日期与上述日期排列，我们会发现剩下的日子）_newarray（“125”，“100”，“65”，而直到这样结束..）

我使用下面的代码本

unsigned int unitFlags =  NSDayCalendarUnit;
NSCalendar *currCalendar = [[NSCalendar alloc]
                            initWithCalendarIdentifier:NSGregorianCalendar];


NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];

[dateFormatter setDateStyle:NSDateFormatterShortStyle];
NSLog(@" currCalendar%@",currCalendar);

NSMutableArray * _newarray = [[NSMutableArray alloc] init];
for (NSString * str in _combinedBirthdates){

    NSDate * toDate = [dateFormatter dateFromString:str];
    NSDateComponents *daysInfo = [currCalendar components:unitFlags fromDate:[NSDate date]  toDate:toDate  options:0];
    int days = [daysInfo day];
    [_newarray addObject:[NSString stringWithFormat:@"%d",days]];
}
NSLog(@" _newarray%@",_newarray);

这就是我得到的输出当我打印_newarray plz帮助我感谢你

_newlymadeArray(
"-1",
"-1",
"-8248",
"-8495",
"-4454",
"-4454",
"-8412",
"-8604",
"-4454",
"-4454",
"-4454",
"-4454",
"-8230",
"-7638",
"-39170",
"-8612",
"-9289",
"-4454",
"-8640",
"-9486",
"-8994",
"-8452",
"-4454",
"-2072",
"-888",
"-8315"
)

Answer 1:

请尽量使用this.I觉得这个可以帮助你。

NSDateFormatter *tempFormatter = [[NSDateFormatter alloc]init];
    [tempFormatter setDateFormat:@"dd/MM/yyyy"];

    NSString *str = [tempFormatter stringFromDate:@"yourStartDate"];
    NSDate *startdate = [tempFormatter dateFromString:str];

    str = [tempFormatter stringFromDate:@"yourEndDate"];
    NSDate *endDate = [tempFormatter dateFromString:str];

    int i = [startdate timeIntervalSince1970];
    int j = [toDate timeIntervalSince1970];

    double X = j-i;

    int days=(int)((double)X/(3600.0*24.00));

Answer 2:

使用下面的代码来比较两个日期传递相同的格式两个日期

NSDateFormatter *dateformat = [[NSDateFormatter alloc]init];
[dateformat setDateFormat:@"dd/MM/yyyy"];
NSString *StrDate1 = [dateformat stringFromDate:[NSDate date]];
NSString *StrDate2 = [dateformat stringFromDate:date2];
NSDate *firstDate = [dateformat dateFromString:StrDate1];
NSDate *secondDate = [dateformat dateFromString:StrDate2];
NSTimeInterval lastDiff = [firstDate timeIntervalSinceNow];
NSTimeInterval todaysDiff = [secondDate timeIntervalSinceNow];
NSTimeInterval dateDiff = todaysDiff - lastDiff;
int day = dateDiff/(3600*24);

 // days are remaining

使用在循环你会门剩下的日子

文章来源: finding out days remain from array of dates [duplicate]