I want to load a JSONL file as JSON objects in python. Is there an easy way to do so?
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问题:
回答1:
In general the code below shall work for you:
import json
result = [json.loads(jline) for jline in jsonl_content.split('\n')]
If that's the response object the result would be:
result = [json.loads(jline) for jline in response.read().split('\n')]
回答2:
Full steps including file operations for beginners like me
Assuming you have a .jsonl
file like:
{"reviewerID": "A2IBPI20UZIR0U", "asin": "1384719342", "reviewerName": "cassandra tu \"Yeah, well, that's just like, u...", "helpful": [0, 0], "reviewText": "Not much to write about here, but it does exactly what it's supposed to. filters out the pop sounds. now my recordings are much more crisp. it is one of the lowest prices pop filters on amazon so might as well buy it, they honestly work the same despite their pricing,", "overall": 5.0, "summary": "good", "unixReviewTime": 1393545600, "reviewTime": "02 28, 2014"}
{"reviewerID": "A14VAT5EAX3D9S", "asin": "1384719342", "reviewerName": "Jake", "helpful": [13, 14], "reviewText": "The product does exactly as it should and is quite affordable.I did not realized it was double screened until it arrived, so it was even better than I had expected.As an added bonus, one of the screens carries a small hint of the smell of an old grape candy I used to buy, so for reminiscent's sake, I cannot stop putting the pop filter next to my nose and smelling it after recording. :DIf you needed a pop filter, this will work just as well as the expensive ones, and it may even come with a pleasing aroma like mine did!Buy this product! :]", "overall": 5.0, "summary": "Jake", "unixReviewTime": 1363392000, "reviewTime": "03 16, 2013"}
This code should work:
import json
with open('./data/my_filename.json', 'r') as json_file:
json_list = list(json_file)
for json_str in json_list:
result = json.loads(json_str)
print("result: {}".format(result))
print(isinstance(result, dict))
About .jsonl
files:
http://jsonlines.org/