Play framework (2.3.5) - Template accessing an inn

问题:

I have a class defined like so (pseudo code):

package com.some.namespace

public class SomeClass {

    protected SomeClass() {}

    // stuff...

    public class SomeInnerClass {

        public SomeInnerClass() {}

        // more stuff (accesses instance variables from SomeClass)...

    }

}

Then in my template I use the reusable block defines like so:

@doSomething(val: com.some.namespace.SomeClass.SomeInnerClass) = {

    // even more stuff...

}

But I get the error:

type SomeInnerClass is not a member of object com.some.namespace.SomeClass

Am I not able to access inner classes within the templates or is this supposed to work? (if it is supposed to work I might need to post my actual code)

回答1:

It should work, but because SomeInnerClass is a dependent type, i.e. dependent on your singleton outer class instance, you need to write it like:

@doSomething(value: com.some.namespace.SomeClass#SomeInnerClass) = {
    // even more stuff...
}

The SomeClass#SomeInnerClass syntax in Scala means, vaguely, a SomeInnerClass from any instance of SomeClass. See this answer for more detail.

If the inner class was static, however, your current SomeClass.SomeInnerClass syntax would be the way to go.