Django的投票向上/向下方法[关闭](Django Vote Up/Down method [c

我想提出一个小的应用程序，可以让网友投票选出的项目向上或向下。我使用Django（和新的吧！）。

我只是想知道，什么是呈现给予好评链接到用户的最佳方式。作为一个链接，按钮或其他什么东西？

我已经做了在PHP这样的事情有不同的框架，但我不知道如果我能做到这一点的方式相同。我应该有向上/向下投票的方法，然后显示一个链接，用户点击。当他们点击它，它执行的方法和刷新页面？

Answer 1:

即插即用：

RedditStyleVoting
实施reddit的风格投票与Django的投票任何型号
http://code.google.com/p/django-voting/wiki/RedditStyleVoting

Answer 2:

这里是我的解决方案的要点。我使用的图像与jQuery / AJAX处理点击。本网站的强烈影响。有一些东西，可以使用一些工作（错误处理在客户端，例如 - 和很多是很可能被重构），但希望该代码是对你有用。

该HTML：

        <div class="vote-buttons">
        {% ifequal thisUserUpVote 0 %}
        <img class="vote-up" src = "images/vote-up-off.png" title="Vote this thread UP. (click again to undo)" />
        {% else %}
        <img class="vote-up selected" src = "images/vote-up-on.png" title="Vote this thread UP. (click again to undo)" />
        {% endifequal %}
        {% ifequal thisUserDownVote 0 %}
        <img class="vote-down" src = "images/vote-down-off.png" title="Vote this thread DOWN if it is innapropriate or incorrect. (click again to undo)" />
        {% else %}
        <img class="vote-down selected" src = "images/vote-down-on.png" title="Vote this thread DOWN if it is innapropriate or incorrect. (click again to undo)" />
        {% endifequal %}
        </div> <!-- .votebuttons -->

jQuery的：

$(document).ready(function() {

    $('div.vote-buttons img.vote-up').click(function() {

        var id = {{ thread.id }};
        var vote_type = 'up';

        if ($(this).hasClass('selected')) {
            var vote_action = 'recall-vote'
            $.post('/ajax/thread/vote', {id:id, type:vote_type, action:vote_action}, function(response) {
                if (isInt(response)) {
                    $('img.vote-up').removeAttr('src')
                        .attr('src', 'images/vote-up-off.png')
                        .removeClass('selected');
                    $('div.vote-tally span.num').html(response);
                }
            });
        } else {

            var vote_action = 'vote'
            $.post('/ajax/thread/vote', {id:id, type:vote_type, action:vote_action}, function(response) {
                if (isInt(response)) {
                    $('img.vote-up').removeAttr('src')
                        .attr('src', 'images/vote-up-on.png')
                        .addClass('selected');
                    $('div.vote-tally span.num').html(response);
                }
            });
        }
    });

处理该AJAX请求Django的观点：

def vote(request):
   thread_id = int(request.POST.get('id'))
   vote_type = request.POST.get('type')
   vote_action = request.POST.get('action')

   thread = get_object_or_404(Thread, pk=thread_id)

   thisUserUpVote = thread.userUpVotes.filter(id = request.user.id).count()
   thisUserDownVote = thread.userDownVotes.filter(id = request.user.id).count()

   if (vote_action == 'vote'):
      if (thisUserUpVote == 0) and (thisUserDownVote == 0):
         if (vote_type == 'up'):
            thread.userUpVotes.add(request.user)
         elif (vote_type == 'down'):
            thread.userDownVotes.add(request.user)
         else:
            return HttpResponse('error-unknown vote type')
      else:
         return HttpResponse('error - already voted', thisUserUpVote, thisUserDownVote)
   elif (vote_action == 'recall-vote'):
      if (vote_type == 'up') and (thisUserUpVote == 1):
         thread.userUpVotes.remove(request.user)
      elif (vote_type == 'down') and (thisUserDownVote ==1):
         thread.userDownVotes.remove(request.user)
      else:
         return HttpResponse('error - unknown vote type or no vote to recall')
   else:
      return HttpResponse('error - bad action')


   num_votes = thread.userUpVotes.count() - thread.userDownVotes.count()

   return HttpResponse(num_votes)

和线程模型的相关部分：

class Thread(models.Model):
    # ...
    userUpVotes = models.ManyToManyField(User, blank=True, related_name='threadUpVotes')
    userDownVotes = models.ManyToManyField(User, blank=True, related_name='threadDownVotes')

Answer 3:

不管你做什么，请确保它是由POST提交的，并没有得到; GET请求不应该改变数据库中的信息。

Answer 4: