Given an input xml file with following structure:
<root>
<record row="1" col="1" val="1" />
<record row="1" col="2" val="2" />
<record row="1" col="3" val="3" />
<record row="1" col="n" val="4" />
<record row="2" col="1" val="5" />
<record row="2" col="3" val="6" />
<record row="2" col="n" val="7" />
<record row="n" col="2" val="8" />
<record row="n" col="3" val="9" />
<record row="n" col="n" val="10" />
</root>
How can I output the following structure using XSLT?
<root>
<row id="1">
<col id="1">1</col>
<col id="2">2</col>
<col id="3">3</col>
<col id="n">4</col>
</row>
<row id="2">
<col id="1">5</col>
<col id="2"></col>
<col id="3">6</col>
<col id="n">7</col>
</row>
<row id="n">
<col id="1"></col>
<col id="2">8</col>
<col id="3">9</col>
<col id="n">10</col>
</row>
</root>
[Note how all columns are output even if there is no related element in input]
EDIT: I may have caused confusion through the use of numbers and letters in my example. The solution I am looking for needs to handle row and column attributes that are non-numeric.
The answers to this question show possible ways to approach the problem:
xslt: How could I use xslt to create a table with multiple columns and rows?
EDIT: A solution that incorporates the techniques seen in the linked question follows.
I am assuming:
- your
@row
and @col
attributes are incrementing numbers that define the position of the record in the table, and they cannot really contain the string "n"
. As such they are not unique throughout the document, which makes them unsuitable as HTML @id
attributes. I substituted them by @title
attributes in my output.
- there are no implicit empty rows (gaps in
@row
continuity will not produce empty rows), only implicit empty cells.
- every
@row
and @col
combination is unique.
This XSLT 1.0 transformation:
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<!-- prepare some keys for later use -->
<xsl:key name="kRecordsByRow" match="record" use="@row" />
<xsl:key name="kRecordsByPos" match="record" use="concat(@row, ',', @col)" />
<!-- find out the highest @col number -->
<xsl:variable name="vMaxCol">
<xsl:for-each select="/root/record">
<xsl:sort select="@col" data-type="number" order="descending" />
<xsl:if test="position() = 1">
<xsl:value-of select="@col" />
</xsl:if>
</xsl:for-each>
</xsl:variable>
<!-- select the <record>s that are the first in their rows -->
<xsl:variable name="vRows" select="
/root/record[
generate-id()
=
generate-id(key('kRecordsByRow', @row)[1])
]
" />
<!-- output basic table structure -->
<xsl:template match="/root">
<table>
<xsl:for-each select="$vRows">
<xsl:sort select="@row" data-type="number" />
<tr title="{@row}">
<xsl:call-template name="td" />
</tr>
</xsl:for-each>
</table>
</xsl:template>
<!-- output the right number of <td>s in each row, empty or not -->
<xsl:template name="td">
<xsl:param name="col" select="1" />
<td title="{$col}">
<xsl:value-of select="key('kRecordsByPos', concat(@row, ',', $col))/@val" />
</td>
<xsl:if test="$col < $vMaxCol">
<xsl:call-template name="td">
<xsl:with-param name="col" select="$col + 1" />
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
…when applied to this (slightly modified) input:
<root>
<record row="1" col="1" val="1" />
<record row="1" col="2" val="2" />
<record row="1" col="3" val="3" />
<record row="1" col="4" val="4" />
<record row="2" col="1" val="5" />
<record row="2" col="3" val="6" />
<record row="2" col="4" val="7" />
<record row="3" col="2" val="8" />
<record row="3" col="3" val="9" />
<record row="3" col="4" val="10" />
</root>
…produces:
<table>
<tr title="1">
<td title="1">1</td>
<td title="2">2</td>
<td title="3">3</td>
<td title="4">4</td>
</tr>
<tr title="2">
<td title="1">5</td>
<td title="2"></td>
<td title="3">6</td>
<td title="4">7</td>
</tr>
<tr title="3">
<td title="1"></td>
<td title="2">8</td>
<td title="3">9</td>
<td title="4">10</td>
</tr>
</table>
- Muenchian grouping is used to select the first
<record>
s of each @row
group
- an
<xsl:key>
is used to pinpoint a record by it's position
- recursion is used to produce a consistent set of
<td>
s, independent of the actual existence of a <record>
at the named position
An XSLT 2.0 solution
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vDoc" as="document-node()"
select="/"/>
<xsl:key name="kColsByRow" match="@col"
use="../@row"/>
<xsl:key name="kRecByRowCol" match="record"
use="concat(@row,'+',@col)"/>
<xsl:template match="/*">
<root>
<xsl:for-each-group select="*/@row"
group-by=".">
<xsl:sort select="current-grouping-key()"
data-type="number"/>
<xsl:variable name="vRow"
select="current-grouping-key()"/>
<row idd="{$vRow}">
<xsl:for-each select=
"1 to max(key('kColsByRow',$vRow)/xs:integer(.))">
<col idd="{.}">
<xsl:value-of select=
"key('kRecByRowCol',
concat($vRow,'+',.),
$vDoc
)
/
@col
"
/>
</col>
</xsl:for-each>
</row>
</xsl:for-each-group>
</root>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document:
<root>
<record row="1" col="1" val="1" />
<record row="1" col="2" val="2" />
<record row="1" col="3" val="3" />
<record row="1" col="10" val="4" />
<record row="2" col="1" val="5" />
<record row="2" col="3" val="6" />
<record row="2" col="10" val="7" />
<record row="10" col="2" val="8" />
<record row="10" col="3" val="9" />
<record row="10" col="10" val="10" />
</root>
produces the wanted result:
<root>
<row idd="1">
<col idd="1">1</col>
<col idd="2">2</col>
<col idd="3">3</col>
<col idd="4"/>
<col idd="5"/>
<col idd="6"/>
<col idd="7"/>
<col idd="8"/>
<col idd="9"/>
<col idd="10">10</col>
</row>
<row idd="2">
<col idd="1">1</col>
<col idd="2"/>
<col idd="3">3</col>
<col idd="4"/>
<col idd="5"/>
<col idd="6"/>
<col idd="7"/>
<col idd="8"/>
<col idd="9"/>
<col idd="10">10</col>
</row>
<row idd="10">
<col idd="1"/>
<col idd="2">2</col>
<col idd="3">3</col>
<col idd="4"/>
<col idd="5"/>
<col idd="6"/>
<col idd="7"/>
<col idd="8"/>
<col idd="9"/>
<col idd="10">10</col>
</row>
</root>