我发现以下问题/回答：
测试MultipartFormData在播放2.0 FakeRequest
但似乎事情已经在播放2.1改变。 我试着适应，像这样的例子：
"Application" should {
"Upload Photo" in {
running(FakeApplication()) {
val data = new MultipartFormData(Map(), List(
FilePart("qqfile", "message", Some("Content-Type: multipart/form-data"),
TemporaryFile(getClass().getResource("/test/photos/DSC03024.JPG").getFile()))
), List())
val Some(result) = routeAndCall(FakeRequest(POST, "/admin/photo/upload", FakeHeaders(), data))
status(result) must equalTo(CREATED)
headers(result) must contain(LOCATION)
contentType(result) must beSome("application/json")
然而，每当我试图运行的要求，我得到一个空指针异常：
[error] ! Upload Photo
[error] NullPointerException: null (PhotoManagementSpec.scala:25)
[error] test.PhotoManagementSpec$$anonfun$1$$anonfun$apply$3$$anonfun$apply$4.apply(PhotoManagementSpec.scala:28)
[error] test.PhotoManagementSpec$$anonfun$1$$anonfun$apply$3$$anonfun$apply$4.apply(PhotoManagementSpec.scala:25)
[error] play.api.test.Helpers$.running(Helpers.scala:40)
[error] test.PhotoManagementSpec$$anonfun$1$$anonfun$apply$3.apply(PhotoManagementSpec.scala:25)
[error] test.PhotoManagementSpec$$anonfun$1$$anonfun$apply$3.apply(PhotoManagementSpec.scala:25)
如果我试图取代只路由弃用routeAndCall（并删除周围结果的选项），我得到一个编译错误，指出它不能写MultipartFormData [TemporaryFile]的实例HTTP响应。
什么是设计这个测试中播放2.1使用Scala的正确方法？
编辑 ：试图修改代码来测试只是控制器：
"Application" should {
"Upload Photo" in {
val data = new MultipartFormData(Map(), List(
FilePart("qqfile", "message", Some("Content-Type: multipart/form-data"),
TemporaryFile(getClass().getResource("/test/photos/DSC03024.JPG").getFile()))
), List())
val result = controllers.Photo.upload()(FakeRequest(POST, "/admin/photo/upload",FakeHeaders(),data))
status(result) must equalTo(OK)
contentType(result) must beSome("text/html")
charset(result) must beSome("utf-8")
contentAsString(result) must contain("Hello Bob")
}
但我现在得到周围的结果，像这样所有的测试类型错误：
[error] found : play.api.libs.iteratee.Iteratee[Array[Byte],play.api.mvc.Result]
[error] required: play.api.mvc.Result
我不明白为什么我得到映射到结果字节数组的迭代符。 这会不会是与我如何使用自定义的身体解析器？ 我的控制器的定义是这样的：
def upload = Action(CustomParsers.multipartFormDataAsBytes) { request =>
request.body.file("qqfile").map { upload =>
使用从这篇文章的形式解析： 从MultipartFormData在内存中Play2 /斯卡拉拉文件
Answer 1:
播放2.3包括httpmime.jar的更新版本，需要一些小的修改。 建立在用玩的可写机制马库斯的解决方案，同时保留了一些从我的播放2.1声道解决方案的语法糖的，这是我想出：
import scala.language.implicitConversions
import java.io.{ByteArrayOutputStream, File}
import org.apache.http.entity.ContentType
import org.apache.http.entity.mime.MultipartEntityBuilder
import org.apache.http.entity.mime.content._
import org.specs2.mutable.Specification
import play.api.http._
import play.api.libs.Files.TemporaryFile
import play.api.mvc.MultipartFormData.FilePart
import play.api.mvc.{Codec, MultipartFormData}
import play.api.test.Helpers._
import play.api.test.{FakeApplication, FakeRequest}
trait FakeMultipartUpload {
implicit def writeableOf_multiPartFormData(implicit codec: Codec): Writeable[MultipartFormData[TemporaryFile]] = {
val builder = MultipartEntityBuilder.create().setBoundary("12345678")
def transform(multipart: MultipartFormData[TemporaryFile]): Array[Byte] = {
multipart.dataParts.foreach { part =>
part._2.foreach { p2 =>
builder.addPart(part._1, new StringBody(p2, ContentType.create("text/plain", "UTF-8")))
}
}
multipart.files.foreach { file =>
val part = new FileBody(file.ref.file, ContentType.create(file.contentType.getOrElse("application/octet-stream")), file.filename)
builder.addPart(file.key, part)
}
val outputStream = new ByteArrayOutputStream
builder.build.writeTo(outputStream)
outputStream.toByteArray
}
new Writeable[MultipartFormData[TemporaryFile]](transform, Some(builder.build.getContentType.getValue))
}
/** shortcut for generating a MultipartFormData with one file part which more fields can be added to */
def fileUpload(key: String, file: File, contentType: String): MultipartFormData[TemporaryFile] = {
MultipartFormData(
dataParts = Map(),
files = Seq(FilePart[TemporaryFile](key, file.getName, Some(contentType), TemporaryFile(file))),
badParts = Seq(),
missingFileParts = Seq())
}
/** shortcut for a request body containing a single file attachment */
case class WrappedFakeRequest[A](fr: FakeRequest[A]) {
def withFileUpload(key: String, file: File, contentType: String) = {
fr.withBody(fileUpload(key, file, contentType))
}
}
implicit def toWrappedFakeRequest[A](fr: FakeRequest[A]) = WrappedFakeRequest(fr)
}
class MyTest extends Specification with FakeMultipartUpload {
"uploading" should {
"be easier than this" in {
running(FakeApplication()) {
val uploadFile = new File("/tmp/file.txt")
val req = FakeRequest(POST, "/upload/path").
withFileUpload("image", uploadFile, "image/gif")
val response = route(req).get
status(response) must equalTo(OK)
}
}
}
}
Answer 2:
我设法与播放2.1本工作基于不同的邮件列表的建议。 下面是我如何做到这一点：
import scala.language.implicitConversions
import java.io.{ ByteArrayOutputStream, File }
import org.apache.http.entity.mime.MultipartEntity
import org.apache.http.entity.mime.content.{ ContentBody, FileBody }
import org.specs2.mutable.Specification
import play.api.http.Writeable
import play.api.test.{ FakeApplication, FakeRequest }
import play.api.test.Helpers._
trait FakeMultipartUpload {
case class WrappedFakeRequest[A](fr: FakeRequest[A]) {
def withMultipart(parts: (String, ContentBody)*) = {
// create a multipart form
val entity = new MultipartEntity()
parts.foreach { part =>
entity.addPart(part._1, part._2)
}
// serialize the form
val outputStream = new ByteArrayOutputStream
entity.writeTo(outputStream)
val bytes = outputStream.toByteArray
// inject the form into our request
val headerContentType = entity.getContentType.getValue
fr.withBody(bytes).withHeaders(CONTENT_TYPE -> headerContentType)
}
def withFileUpload(fileParam: String, file: File, contentType: String) = {
withMultipart(fileParam -> new FileBody(file, contentType))
}
}
implicit def toWrappedFakeRequest[A](fr: FakeRequest[A]) = WrappedFakeRequest(fr)
// override Play's equivalent Writeable so that the content-type header from the FakeRequest is used instead of application/octet-stream
implicit val wBytes: Writeable[Array[Byte]] = Writeable(identity, None)
}
class MyTest extends Specification with FakeMultipartUpload {
"uploading" should {
"be easier than this" in {
running(FakeApplication()) {
val uploadFile = new File("/tmp/file.txt")
val req = FakeRequest(POST, "/upload/path").
withFileUpload("image", uploadFile, "image/gif")
val response = route(req).get
status(response) must equalTo(OK)
}
}
}
}
Answer 3:
我修改亚历克斯的代码到更好的集成作为一个可写为游戏2.2.2
package test
import play.api.http._
import play.api.mvc.MultipartFormData.FilePart
import play.api.libs.iteratee._
import play.api.libs.Files.TemporaryFile
import play.api.mvc.{Codec, MultipartFormData }
import java.io.{FileInputStream, ByteArrayOutputStream}
import org.apache.commons.io.IOUtils
import org.apache.http.entity.mime.MultipartEntity
import org.apache.http.entity.mime.content._
object MultipartWriteable {
/**
* `Writeable` for multipart/form-data.
*
*/
implicit def writeableOf_multiPartFormData(implicit codec: Codec): Writeable[MultipartFormData[TemporaryFile]] = {
val entity = new MultipartEntity()
def transform(multipart: MultipartFormData[TemporaryFile]):Array[Byte] = {
multipart.dataParts.foreach { part =>
part._2.foreach { p2 =>
entity.addPart(part._1, new StringBody(p2))
}
}
multipart.files.foreach { file =>
val part = new FileBody(file.ref.file, file.filename, file.contentType.getOrElse("application/octet-stream"), null)
entity.addPart(file.key, part)
}
val outputStream = new ByteArrayOutputStream
entity.writeTo(outputStream)
val bytes = outputStream.toByteArray
outputStream.close
bytes
}
new Writeable[MultipartFormData[TemporaryFile]](transform, Some(entity.getContentType.getValue))
}
}
这样，就可以写的东西是这样的：
val filePart:MultipartFormData.FilePart[TemporaryFile] = MultipartFormData.FilePart(...)
val fileParts:Seq[MultipartFormData.FilePart[TemporaryFile]] = Seq(filePart)
val dataParts:Map[String, Seq[String]] = ...
val multipart = new MultipartFormData[TemporaryFile](dataParts, fileParts, List(), List())
val request = FakeRequest(POST, "/url", FakeHeaders(), multipart)
var result = route(request).get
Answer 4:
继EEColor的建议下，我得到了以下工作：
"Upload Photo" in {
val file = scala.io.Source.fromFile(getClass().getResource("/photos/DSC03024.JPG").getFile())(scala.io.Codec.ISO8859).map(_.toByte).toArray
val data = new MultipartFormData(Map(), List(
FilePart("qqfile", "DSC03024.JPG", Some("image/jpeg"),
file)
), List())
val result = controllers.Photo.upload()(FakeRequest(POST, "/admin/photos/upload",FakeHeaders(),data))
status(result) must equalTo(CREATED)
headers(result) must haveKeys(LOCATION)
contentType(result) must beSome("application/json")
}
Answer 5:
这里是我的可写[AnyContentAsMultipartFormData]的版本：
import java.io.File
import play.api.http.{HeaderNames, Writeable}
import play.api.libs.Files.TemporaryFile
import play.api.mvc.MultipartFormData.FilePart
import play.api.mvc.{AnyContentAsMultipartFormData, Codec, MultipartFormData}
object MultipartFormDataWritable {
val boundary = "--------ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"
def formatDataParts(data: Map[String, Seq[String]]) = {
val dataParts = data.flatMap { case (key, values) =>
values.map { value =>
val name = s""""$key""""
s"--$boundary\r\n${HeaderNames.CONTENT_DISPOSITION}: form-data; name=$name\r\n\r\n$value\r\n"
}
}.mkString("")
Codec.utf_8.encode(dataParts)
}
def filePartHeader(file: FilePart[TemporaryFile]) = {
val name = s""""${file.key}""""
val filename = s""""${file.filename}""""
val contentType = file.contentType.map { ct =>
s"${HeaderNames.CONTENT_TYPE}: $ct\r\n"
}.getOrElse("")
Codec.utf_8.encode(s"--$boundary\r\n${HeaderNames.CONTENT_DISPOSITION}: form-data; name=$name; filename=$filename\r\n$contentType\r\n")
}
val singleton = Writeable[MultipartFormData[TemporaryFile]](
transform = { form: MultipartFormData[TemporaryFile] =>
formatDataParts(form.dataParts) ++
form.files.flatMap { file =>
val fileBytes = Files.readAllBytes(Paths.get(file.ref.file.getAbsolutePath))
filePartHeader(file) ++ fileBytes ++ Codec.utf_8.encode("\r\n")
} ++
Codec.utf_8.encode(s"--$boundary--")
},
contentType = Some(s"multipart/form-data; boundary=$boundary")
)
}
implicit val anyContentAsMultipartFormWritable: Writeable[AnyContentAsMultipartFormData] = {
MultipartFormDataWritable.singleton.map(_.mdf)
}
它改编自（和一些错误修正）： https://github.com/jroper/playframework/blob/multpart-form-data-writeable/framework/src/play/src/main/scala/play/api/http/ Writeable.scala＃L108
看到这里整个帖子，如果你有兴趣： http://tech.fongmun.com/post/125479939452/test-multipartformdata-in-play
Answer 6:
对于我来说，这个问题最好的解决办法是亚历克斯Varju一个
以下是更新的游戏2.5版本：
object FakeMultipartUpload {
implicit def writeableOf_multiPartFormData(implicit codec: Codec): Writeable[AnyContentAsMultipartFormData] = {
val builder = MultipartEntityBuilder.create().setBoundary("12345678")
def transform(multipart: AnyContentAsMultipartFormData): ByteString = {
multipart.mdf.dataParts.foreach { part =>
part._2.foreach { p2 =>
builder.addPart(part._1, new StringBody(p2, ContentType.create("text/plain", "UTF-8")))
}
}
multipart.mdf.files.foreach { file =>
val part = new FileBody(file.ref.file, ContentType.create(file.contentType.getOrElse("application/octet-stream")), file.filename)
builder.addPart(file.key, part)
}
val outputStream = new ByteArrayOutputStream
builder.build.writeTo(outputStream)
ByteString(outputStream.toByteArray)
}
new Writeable(transform, Some(builder.build.getContentType.getValue))
}
}
Answer 7:
在播放的2.6.x您可以通过以下方式来测试文件上传API编写测试用例：
class HDFSControllerTest extends Specification {
"HDFSController" should {
"return 200 Status for file Upload" in new WithApplication {
val tempFile = SingletonTemporaryFileCreator.create("txt","csv")
tempFile.deleteOnExit()
val data = new MultipartFormData[TemporaryFile](Map(),
List(FilePart("metadata", "text1.csv", Some("text/plain"), tempFile)), List())
val res: Option[Future[Result]] = route(app, FakeRequest(POST, "/api/hdfs").withMultipartFormDataBody(data))
print(contentAsString(res.get))
res must beSome.which(status(_) == OK)
}
}
}
文章来源: Writing a test case for file uploads in Play 2.1 and Scala
