我有1点UITextfield密码在我的iPhone应用程序。
我想验证此文本框与下面的验证。
- 必须至少包含10个字符
- 必须包含至少一个小写字母，一个大写字母，一个数字和一个特殊字符
- 有效特殊字符-
@#$%^&+=^.*(?=.{10,})(?=.*d)(?=.*[az])(?=.*[AZ])(?=.*[@#$%^&+=]).*$
我怎样才能限制UITextField与上述要求？
Answer 1:
这是我会怎么做。 验证应在年底完成，当用户在密码已键入，而不是在between.I不会使用NSRegularExpression 。
-(void)textFieldDidEndEditing:(UITextField *)textField{
int numberofCharacters = 0;
BOOL lowerCaseLetter,upperCaseLetter,digit,specialCharacter = 0;
if([textField.text length] >= 10)
{
for (int i = 0; i < [textfield.text length]; i++)
{
unichar c = [textfield.text characterAtIndex:i];
if(!lowerCaseLetter)
{
lowerCaseLetter = [[NSCharacterSet lowercaseLetterCharacterSet] characterIsMember:c];
}
if(!upperCaseLetter)
{
upperCaseLetter = [[NSCharacterSet uppercaseLetterCharacterSet] characterIsMember:c];
}
if(!digit)
{
digit = [[NSCharacterSet decimalDigitCharacterSet] characterIsMember:c];
}
if(!specialCharacter)
{
specialCharacter = [[NSCharacterSet symbolCharacterSet] characterIsMember:c];
}
}
if(specialCharacter && digit && lowerCaseLetter && upperCaseLetter)
{
//do what u want
}
else
{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Please Ensure that you have at least one lower case letter, one upper case letter, one digit and one special character"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
}
else
{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Please Enter at least 10 password"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
}
希望这可以帮助...
Answer 2:
您也可以通过做这个Regex 。 下面是我提供给你几个例子：
// *** Validation for Password ***
// "^(?=.*[A-Za-z])(?=.*\\d)[A-Za-z\\d]{8,}$" --> (Minimum 8 characters at least 1 Alphabet and 1 Number)
// "^(?=.*[A-Za-z])(?=.*\\d)(?=.*[$@$!%*#?&])[A-Za-z\\d$@$!%*#?&]{8,16}$" --> (Minimum 8 and Maximum 16 characters at least 1 Alphabet, 1 Number and 1 Special Character)
// "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)[a-zA-Z\\d]{8,}$" --> (Minimum 8 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet and 1 Number)
// "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]{8,}" --> (Minimum 8 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet, 1 Number and 1 Special Character)
// "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]{8,10}" --> (Minimum 8 and Maximum 10 characters at least 1 Uppercase Alphabet, 1 Lowercase Alphabet, 1 Number and 1 Special Character)
从列表中第四个是你的情况下，下面的代码片段展示了如何使用它：
-(BOOL)isValidPassword:(NSString *)passwordString
{
NSString *stricterFilterString = @"^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]{10,}";
NSPredicate *passwordTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", stricterFilterString];
return [passwordTest evaluateWithObject:passwordString];
}
使用方法：
if(![self isValidPassword:txtPassword.text]) {
/* Show alert: "Password must be minimum 10 characters,
at least 1 Uppercase Alphabet, 1 Lowercase Alphabet,
1 Number and 1 Special Character" */
}
else {
// Password is valid
}
Answer 3:
条件 ：密码至少含有一个8个字符，1个大写字母和1号
解决方案在斯威夫特3
你可以写字符串拓这样的，
extension String {
func isValidPassword() -> Bool {
let regularExpression = "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]{8,}"
let passwordValidation = NSPredicate.init(format: "SELF MATCHES %@", regularExpression)
return passwordValidation.evaluate(with: self)
}
}
//Example 1
var password = "@Abcdef011" //string from UITextField (Password)
password.isValidPassword() // -> true
//Example 2
var password = "Abcdef011" //string from UITextField
password.isValidPassword() // -> false
或者你可以写函数像这样，
func validate(password: String) -> Bool
{
let regularExpression = "^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$!%*?&])[A-Za-z\\d$@$!%*?&]{8,}"
let passwordValidation = NSPredicate.init(format: "SELF MATCHES %@", regularExpression)
return passwordValidation.evaluate(with: password)
}
这会给你同样的结果。
Answer 4:
您可以使用下面的函数只是传递一个密码字符串验证您的密码验证，这将返回BOOL值。
-(BOOL) isPasswordValid:(NSString *)pwd {
NSCharacterSet *upperCaseChars = [NSCharacterSet characterSetWithCharactersInString:@"ABCDEFGHIJKLKMNOPQRSTUVWXYZ"];
NSCharacterSet *lowerCaseChars = [NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyz"];
//NSCharacterSet *numbers = [NSCharacterSet characterSetWithCharactersInString:@"0123456789"];
if ( [pwd length]<6 || [pwd length]>20 )
return NO; // too long or too short
NSRange rang;
rang = [pwd rangeOfCharacterFromSet:[NSCharacterSet letterCharacterSet]];
if ( !rang.length )
return NO; // no letter
rang = [pwd rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]];
if ( !rang.length )
return NO; // no number;
rang = [pwd rangeOfCharacterFromSet:upperCaseChars];
if ( !rang.length )
return NO; // no uppercase letter;
rang = [pwd rangeOfCharacterFromSet:lowerCaseChars];
if ( !rang.length )
return NO; // no lowerCase Chars;
return YES;
}
Answer 5:
斯威夫特3
检查，如果密码是强？
- 长度大于或等于8
- 小写
- 大写
- 小数位数
特殊字符，如！@＃$％^＆*（）_- +可选
为什么我不能用正则表达式？
因为它是很难支持正则表达式语法保留字符。
func isValidated(_ password: String) -> Bool {
var lowerCaseLetter: Bool = false
var upperCaseLetter: Bool = false
var digit: Bool = false
var specialCharacter: Bool = false
if password.characters.count >= 8 {
for char in password.unicodeScalars {
if !lowerCaseLetter {
lowerCaseLetter = CharacterSet.lowercaseLetters.contains(char)
}
if !upperCaseLetter {
upperCaseLetter = CharacterSet.uppercaseLetters.contains(char)
}
if !digit {
digit = CharacterSet.decimalDigits.contains(char)
}
if !specialCharacter {
specialCharacter = CharacterSet.punctuationCharacters.contains(char)
}
}
if specialCharacter || (digit && lowerCaseLetter && upperCaseLetter) {
//do what u want
return true
}
else {
return false
}
}
return false
}
let isVaildPass:Bool = isValidated("Test**00+-")
print(isVaildPass)
Answer 6:
使用正则表达式（NSRegularExpression类有关于如何编写彭定康本身文档），然后：
- (BOOL)textField:(UITextField *)theTextField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
//delete
if (string.length == 0) {
return YES;
}
if (self.regEx) {
NSMutableString* check = [NSMutableString stringWithString:theTextField.text];
[check replaceCharactersInRange:range withString:string];
NSTextCheckingResult* match = [self.regEx firstMatchInString:check options:0 range:NSMakeRange(0, [check length])];
if (match.range.length != check.length) {
return NO;
}
}
}
警告：限制输入这种方式实在是混淆了用户。 您键入和类型，您键入只是不出现的人物！
我想，也许有一个红色的小走（！）旁边的测试场，但我总是允许输入本身！
Answer 7:
我对这种形式优雅的解决方案（如注册）的，你有很多的验证
我在我的自定义的UITextField出口：
@IBInspectable var regexpValidation: String? = nil
在故事板，我可以通过属性检查器访问它，并把正则表达式串那样（电子邮件）：
[a-z0-9!#$%&'*+/=?^_ {|}〜 - +（：[A-Z0-9＃$％＆？！]' * + / = ^ _？ {|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?
然后在我的子类，我有这个计算的变种：
@IBInspectable VAR regexpValidation：字符串？ =零//可选，在InterfaceBuilder中设置此
var inputIsValid: Bool {
get {
if let expr = regexpValidation {
return (text.rangeOfString(expr, options: NSStringCompareOptions.RegularExpressionSearch, range: nil, locale: nil) != nil)
} else {
return true
}
}
}
这可以这样来使用：
override func resignFirstResponder() -> Bool {
if (inputIsValid) {
return super.resignFirstResponder()
}
else {
text = ""
return false
}
}
Answer 8:
对我来说最好的办法是使用NSPredicate和正则表达式。 这是你的情况正则表达式^(?=.{10,})(?=.*[0-9])(?=.*[a-zA-Z])([@#$%^&=a-zA-Z0-9_-]+)$
客观的C代码：
NSString *regex = @"^(?=.{10,})(?=.*[0-9])(?=.*[a-zA-Z])([@#$%^&=a-zA-Z0-9_-]+)$";
NSPredicate *passwordTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", regex];
BOOL isValid = [passwordTest evaluateWithObject:yourTextfield.text];
Answer 9:
你需要写您的验证码在此委托方法UITextField
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
您可能希望参考执行几个环节
如何使用iOS版SDK的正则表达式
iOS的文本字段验证
Answer 10:
使用control:isValidObject:所述的方法NSTextFieldDelegate协议，它允许你验证的NSTextField的值。 假设你把所有的接口建设者的点点滴滴正确配置，你可能会做这样的事情：
@interface PreferencesController : NSWindowController <NSTextFieldDelegate> {
IBOutlet NSTextField *username, *password;
}
@end
@implementation PreferencesController
- (BOOL)control:(NSControl *)control isValidObject:(id)object
{
if (control == password) {
// Perform validation and return YES or NO
}
return YES;
}
@end
文章来源: Password validation in UITextField in iOS
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