What can I use to call the OS to open a URL in whatever browser the user has as default? Not worried about cross-OS compatibility; if it works in linux thats enough for me!
问题:
回答1:
Here is how to open the user's default browser with a given url:
import webbrowser
webbrowser.open(url[, new=0[, autoraise=True]])
Here is the documentation about this functionality. It's part of Python's stdlibs:
http://docs.python.org/library/webbrowser.html
I have tested this successfully on Linux, Ubuntu 10.10.
回答2:
Personally I really wouldn't use the webbrowser
module.
It's a complicated mess of sniffing for particular browsers, which will won't find the user's default browser if they have more than one installed, and won't find a browser if it doesn't know the name of it (eg Chrome).
Better on Windows is simply to use the os.startfile
function, which also works on a URL. On OS X, you can use the open
system command. On Linux there's xdg-open
, a freedesktop.org standard command supported by GNOME, KDE and XFCE.
if sys.platform=='win32':
os.startfile(url)
elif sys.platform=='darwin':
subprocess.Popen(['open', url])
else:
try:
subprocess.Popen(['xdg-open', url])
except OSError:
print 'Please open a browser on: '+url
This will give a better user experience on mainstream platforms. You could fall back to webbrowser
on other platforms, perhaps. Though most likely if you're on an obscure/unusual/embedded OS where none of the above work, chances are webbrowser
will fail too.
回答3:
You can use the webbrowser module.
webbrowser.open(url)
回答4:
Then how about mixing codes of @kobrien and @bobince up:
import subprocess
import webbrowser
import sys
url = 'http://test.com'
if sys.platform == 'darwin': # in case of OS X
subprocess.Popen(['open', url])
else:
webbrowser.open_new_tab(url)
回答5:
Have a look at the webbrowser module.