有没有办法在另一个字符串替换字符串的所有出现std::string ？
例如：
void SomeFunction(std::string& str)
{
str = str.replace("hello", "world"); //< I'm looking for something nice like this
}
Answer 1:
为什么不实现自己更换？
void myReplace(std::string& str,
const std::string& oldStr,
const std::string& newStr)
{
std::string::size_type pos = 0u;
while((pos = str.find(oldStr, pos)) != std::string::npos){
str.replace(pos, oldStr.length(), newStr);
pos += newStr.length();
}
}
Answer 2:
#include <boost/algorithm/string.hpp> // include Boost, a C++ library
...
std::string target("Would you like a foo of chocolate. Two foos of chocolate?");
boost::replace_all(target, "foo", "bar");
下面是官方文档上replace_all。
Answer 3:
在C ++ 11，你可以做到这一点作为一个班轮通过调用regex_replace ：
#include <string>
#include <regex>
using std::string;
string do_replace( string const & in, string const & from, string const & to )
{
return std::regex_replace( in, std::regex(from), to );
}
string test = "Remove all spaces";
std::cout << do_replace(test, " ", "") << std::endl;
输出：
Removeallspaces
Answer 4:
为什么不返回修改后的字符串？
std::string ReplaceString(std::string subject, const std::string& search,
const std::string& replace) {
size_t pos = 0;
while((pos = subject.find(search, pos)) != std::string::npos) {
subject.replace(pos, search.length(), replace);
pos += replace.length();
}
return subject;
}
如果您需要的性能，下面是修改输入字符串的优化功能，它不会创建字符串的副本：
void ReplaceStringInPlace(std::string& subject, const std::string& search,
const std::string& replace) {
size_t pos = 0;
while((pos = subject.find(search, pos)) != std::string::npos) {
subject.replace(pos, search.length(), replace);
pos += replace.length();
}
}
测试：
std::string input = "abc abc def";
std::cout << "Input string: " << input << std::endl;
std::cout << "ReplaceString() return value: "
<< ReplaceString(input, "bc", "!!") << std::endl;
std::cout << "ReplaceString() input string not changed: "
<< input << std::endl;
ReplaceStringInPlace(input, "bc", "??");
std::cout << "ReplaceStringInPlace() input string modified: "
<< input << std::endl;
输出：
Input string: abc abc def
ReplaceString() return value: a!! a!! def
ReplaceString() input string not modified: abc abc def
ReplaceStringInPlace() input string modified: a?? a?? def
Answer 5:
就地我的模板化的在线查找和替换：
template<class T>
int inline findAndReplace(T& source, const T& find, const T& replace)
{
int num=0;
typename T::size_t fLen = find.size();
typename T::size_t rLen = replace.size();
for (T::size_t pos=0; (pos=source.find(find, pos))!=T::npos; pos+=rLen)
{
num++;
source.replace(pos, fLen, replace);
}
return num;
}
（如果你想连续运行此等使用），它返回取代的项目数的计数。 要使用它：
std::string str = "one two three";
int n = findAndReplace(str, "one", "1");
Answer 6:
最简单的方法（提供近你写的东西）是使用Boost.Regex ，特别是regex_replace 。
的std :: string已建成的发现（）和替换（）方法，但他们更繁琐用，因为它们需要处理指标和字符串长度工作。
Answer 7:
我相信这会工作。 它需要为const char *的一个参数。
//params find and replace cannot be NULL
void FindAndReplace( std::string& source, const char* find, const char* replace )
{
//ASSERT(find != NULL);
//ASSERT(replace != NULL);
size_t findLen = strlen(find);
size_t replaceLen = strlen(replace);
size_t pos = 0;
//search for the next occurrence of find within source
while ((pos = source.find(find, pos)) != std::string::npos)
{
//replace the found string with the replacement
source.replace( pos, findLen, replace );
//the next line keeps you from searching your replace string,
//so your could replace "hello" with "hello world"
//and not have it blow chunks.
pos += replaceLen;
}
}
Answer 8:
#include <iostream>
#include <string>
#include <boost/algorithm/string.hpp>
#include <boost/tokenizer.hpp>
#include <boost/foreach.hpp>
using namespace boost::algorithm;
using namespace std;
using namespace boost;
void highlighter(string terms, string text) {
char_separator<char> sep(" ");
tokenizer<char_separator<char> > tokens(terms, sep);
BOOST_FOREACH(string term, tokens) {
boost::replace_all(text, term, "<b>" + term + "</b>");
}
cout << text << endl;
}
int main(int argc, char **argv)
{
cout << "Search term highlighter" << endl;
string text("I love boost library, and this is a test of boost library!");
highlighter("love boost", text);
}
我爱 Boost库，这是提升图书馆的考验！
Answer 9:
// Replace all occurrences of searchStr in str with replacer
// Each match is replaced only once to prevent an infinite loop
// The algorithm iterates once over the input and only concatenates
// to the output, so it should be reasonably efficient
std::string replace(const std::string& str, const std::string& searchStr,
const std::string& replacer)
{
// Prevent an infinite loop if the input is empty
if (searchStr == "") {
return str;
}
std::string result = "";
size_t pos = 0;
size_t pos2 = str.find(searchStr, pos);
while (pos2 != std::string::npos) {
result += str.substr(pos, pos2-pos) + replacer;
pos = pos2 + searchStr.length();
pos2 = str.find(searchStr, pos);
}
result += str.substr(pos, str.length()-pos);
return result;
}
Answer 10:
#include <string>
using std::string;
void myReplace(string& str,
const string& oldStr,
const string& newStr) {
if (oldStr.empty()) {
return;
}
for (size_t pos = 0; (pos = str.find(oldStr, pos)) != string::npos;) {
str.replace(pos, oldStr.length(), newStr);
pos += newStr.length();
}
}
对于oldStr是空的检查是很重要的。 如果出于某种原因，参数为空，你会陷入一个死循环。
但是，是使用尝试，如果你能测试C ++ 11或推进方案。
文章来源: How do I Search/Find and Replace in a standard string?
