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问题:
I'm currently working on my Laravel app and to prevent spam I decided that only active users are able to login.
I'm currently using Laravel's login system just like in Laravel's official website tutorial, here's my form action:
<form class="form-horizontal" role="form" method="POST" action="{{ url('/auth/login') }}">
This works completely fine, however I'd like to check the user's active, if not active it would be redirected to the activation page, otherwise it would login.
Is there a simple way to do this or am I obligated to make a new controller, routes and more verifications? Thank you.
Edit: Forgot to mention that I have a 'active' column in my database.
回答1:
Laravel 5.4 / 5.5
Override the default login()
function by placing this function in your LoginController
:
public function login(\Illuminate\Http\Request $request) {
$this->validateLogin($request);
// If the class is using the ThrottlesLogins trait, we can automatically throttle
// the login attempts for this application. We'll key this by the username and
// the IP address of the client making these requests into this application.
if ($this->hasTooManyLoginAttempts($request)) {
$this->fireLockoutEvent($request);
return $this->sendLockoutResponse($request);
}
// This section is the only change
if ($this->guard()->validate($this->credentials($request))) {
$user = $this->guard()->getLastAttempted();
// Make sure the user is active
if ($user->active && $this->attemptLogin($request)) {
// Send the normal successful login response
return $this->sendLoginResponse($request);
} else {
// Increment the failed login attempts and redirect back to the
// login form with an error message.
$this->incrementLoginAttempts($request);
return redirect()
->back()
->withInput($request->only($this->username(), 'remember'))
->withErrors(['active' => 'You must be active to login.']);
}
}
// If the login attempt was unsuccessful we will increment the number of attempts
// to login and redirect the user back to the login form. Of course, when this
// user surpasses their maximum number of attempts they will get locked out.
$this->incrementLoginAttempts($request);
return $this->sendFailedLoginResponse($request);
}
Overriding the login()
method in this way is recommended over many of the other answers on this question because it allows you to still use many of the more advanced authentication functionality of Laravel 5.4+ such as login throttling, multiple authentication guard drivers/providers, etc. while still allowing you to set a custom error message.
Laravel 5.3
Change or override your postLogin()
function in your AuthController
to look like this:
public function postLogin(Request $request)
{
$this->validate($request, [
'email' => 'required|email', 'password' => 'required',
]);
$credentials = $this->getCredentials($request);
// This section is the only change
if (Auth::validate($credentials)) {
$user = Auth::getLastAttempted();
if ($user->active) {
Auth::login($user, $request->has('remember'));
return redirect()->intended($this->redirectPath());
} else {
return redirect($this->loginPath()) // Change this to redirect elsewhere
->withInput($request->only('email', 'remember'))
->withErrors([
'active' => 'You must be active to login.'
]);
}
}
return redirect($this->loginPath())
->withInput($request->only('email', 'remember'))
->withErrors([
'email' => $this->getFailedLoginMessage(),
]);
}
This code redirects back to the login page with an error message about the user being inactive. If you want to redirect to an authentication page you would change the line I marked with the comment Change this to redirect elsewhere
.
回答2:
In Laravel 5.4 open Auth/LoginController.php
and add this function:
/**
* Get the needed authorization credentials from the request.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
protected function credentials(\Illuminate\Http\Request $request)
{
//return $request->only($this->username(), 'password');
return ['email' => $request->{$this->username()}, 'password' => $request->password, 'status' => 1];
}
And you are done..!
回答3:
This solution is based on Can Celik's idea and was tested with Laravel 5.3.
protected function validateLogin(Request $request)
{
$this->validate($request, [
$this->username() => 'required|exists:users,' . $this->username() . ',active,1',
'password' => 'required',
]);
}
The last two comma-separated parameters (active,1
) act as a WHERE clause (WHERE active = '1'
) and can be alternatively written this way:
protected function validateLogin(Request $request)
{
$this->validate($request, [
$this->username() => [
'required',
Rule::exists('users')->where(function ($query) {
$query->where('active', 1);
}),
],
'password' => 'required'
]);
}
Normally, the validation method only checks if email and password fields are filled out. With the modification above we require that a given email address is found in a DB row with active
value set to 1.
UPDATE (tested with Laravel 5.5):
You can also customize the message:
protected function validateLogin(Request $request)
{
$this->validate($request, [
$this->username() => 'required|exists:users,' . $this->username() . ',active,1',
'password' => 'required',
], [
$this->username() . '.exists' => 'The selected email is invalid or the account has been disabled.'
]);
}
Note that the above message will be shown both when a given email address doesn't exist or when the account is disabled.
回答4:
in AuthController override method getCredentials like this:
protected function getCredentials(Request $request) {
$request['active'] = TRUE;
return $request->only($this->loginUsername(), 'password', 'active');
}
make sure you have the column active on user table...
回答5:
You don't have to override the whole function. You can just change the Validator in AuthController to achieve that adding "exists:table,column" validation.
Let's assume that you have a users table with email,password and active fields.
'email' => 'exists:users,email,active,1'
Here is the validotor function should look like in AuthController.php
protected function validator(array $data)
{
return Validator::make($data, [
'email' => 'required|email|max:255|exists:users,email,active,1',
'password' => 'required|confirmed'
]);
}
or if you are using soft deletes this should work too.
'email' => 'exists:users,email,deleted_at,NULL'
You can also check out the validation rule at this link http://laravel.com/docs/5.1/validation#rule-exists
回答6:
I check user is actived by overwrite sendLoginResponse function in LoginController
protected function sendLoginResponse(Request $request)
{
if($this->guard()->user()->active == 0){
$this->guard()->logout();
return redirect()->back()
->withInput($request->only($this->username(), 'remember'))
->withErrors(['active' => 'User in not activated.']);
}
$request->session()->regenerate();
$this->clearLoginAttempts($request);
return $this->authenticated($request, $this->guard()->user())
?: redirect()->intended($this->redirectPath());
}
回答7:
If someone uses ajax request on login and wants to have custom message, here is how I achieved this in login controller:
login() function
// This section is the only change
if ($this->guard()->validate($this->credentials($request))) {
$user = $this->guard()->getLastAttempted();
// Make sure the user is active
if ($user->status == 1 && $this->attemptLogin($request)) {
// Send the normal successful login response
return $this->sendLoginResponse($request);
} else {
// Increment the failed login attempts and redirect back to the
// login form with an error message.
$this->incrementLoginAttempts($request);
return $this->sendFailedLoginResponse($request, true);
}
}
And other functions
public function sendLoginResponse(Request $request)
{
$redirectTo = false;
if ($request->headers->get('referer') == env('APP_URL') . '/' || $request->headers->get('referer') == env('APP_URL') . '/login') {
$redirectTo = $this->redirectPath();
}
if ($request->expectsJson()) {
return response()->json(['status' => true, 'user' => auth()->user(), 'redirectTo' => $redirectTo, 'fragments' => [
'#main-nav' => view('includes.nav')->render()
]]);
} else {
return redirect($redirectTo);
}
}
public function sendFailedLoginResponse(Request $request, $user_not_active = fasle)
{
if ($user_not_active) {
return response()->json(['status' => false, 'email' => 'Your account is not active.']);
}
return response()->json(['status' => false, 'email' => 'Incorrect login credentials.']);
}
回答8:
In case anyone is came here looking for information on Laravel 5.4/5.5, and that allows for a custom message just for this scenario (not a combined message) here's the answer for that from https://laracasts.com/discuss/channels/laravel/user-account-status
Override the 'authenticated' method within your'app/Http/Controllers/Auth/LoginController.php` file:
/**
* The user has been authenticated.
*
* @param \Illuminate\Http\Request $request
* @param mixed $user
* @return mixed
*/
protected function authenticated(Request $request, $user)
{
if ($user->status_id == 2) { // or whatever status column name and value indicates a blocked user
$message = 'Some message about status';
// Log the user out.
$this->logout($request);
// Return them to the log in form.
return redirect()->back()
->withInput($request->only($this->username(), 'remember'))
->withErrors([
// This is where we are providing the error message.
$this->username() => $message,
]);
}
}
回答9:
Thanks @Can_Celik
this was how I was able to solve my issue becos i was using json response
with jquery.
/**
* Validate the user login request.
*
* @param \Illuminate\Http\Request $request
* @return void
*/
protected function validateLogin(Request $request)
{
$this->validate($request, [
'email' => 'required|email|exists:users_table,email,account_status_colunm,active_value',
'password' => 'required',
]);
}
then in the validation.php
file add this to your Custom Validation strings
...
'email' => [
'exists' => 'Account has been disabled. Contact our team.'
],
that's about all...works fine
...