我设法修改程序,以中国平安等计算机并得到平计数。 我怎么能解析出time = ?ms
从平盘点结果,实时?
码:
public static void main(String[] args) {
String ip = "192.168.1.1 -n 10";
String pingResult = "";
String pingCmd = "ping " + ip;
try{
Runtime r = Runtime.getRuntime();
Process p = r.exec(pingCmd);
BufferedReader in = new BufferedReader(new InputStreamReader(p.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
System.out.println(inputLine);
pingResult += inputLine;
}
in.close();
} catch(Exception e) {
System.out.println(e);
}
}
输出:
Reply from 192.168.1.1: bytes=32 time=2ms TTL=64
Reply from 192.168.1.1: bytes=32 time=4ms TTL=64
Reply from 192.168.1.1: bytes=32 time=2ms TTL=64
Reply from 192.168.1.1: bytes=32 time=2ms TTL=64
Reply from 192.168.1.1: bytes=32 time=20ms TTL=64
Reply from 192.168.1.1: bytes=32 time=9ms TTL=64
Reply from 192.168.1.1: bytes=32 time=3ms TTL=64
Reply from 192.168.1.1: bytes=32 time=2ms TTL=64
Reply from 192.168.1.1: bytes=32 time=2ms TTL=64
Reply from 192.168.1.1: bytes=32 time=3ms TTL=64
Ping statistics for 192.168.1.1:
Packets: Sent = 10, Received = 10, Lost = 0 (0% loss),
Approximate round trip times in milli-seconds:
Minimum = 2ms, Maximum = 20ms, Average = 4ms
难道我需要声明一个变量,并写出了“时间=?毫秒”到使用的BufferedReader文本文件里?
我在寻找线索,谢谢。