该FB共享器弹出窗口显示网页,而不是我已经插在PHP链接元数据的数据。
<a href="http://www.facebook.com/sharer/sharer.php?s=100&p%5Btitle%5D=Google&p%5Burl%5D=http%3A%2F%2Fwww.google.com&p%5Bsummary%5D=Google search engine&p%5Bimages%5D%5B0%5D=https://www.google.com/images/srpr/logo3w.png
"onClick="return fbs_click(626, 305)" target="_blank" title="Share">FACEBOOK</a>
看来要由JavaScript引起的
<script type="text/javascript">
function fbs_click(width, height) {
var leftPosition, topPosition;
leftPosition = (window.screen.width / 2) - ((width / 2) + 10);
topPosition = (window.screen.height / 2) - ((height / 2) + 50);
var windowFeatures = "status=no,height=" + height + ",width=" + width + ",resizable=no,left=" + leftPosition + ",top=" + topPosition + ",screenX=" + leftPosition + ",screenY=" + topPosition + ",toolbar=no,menubar=no,scrollbars=no,location=no,directories=no";
u=location.href;
t=document.title;
window.open('http://www.facebook.com/sharer.php?u='+encodeURIComponent(u)+'&t='+encodeURIComponent(t),'sharer', windowFeatures);
return false;
}
</script>
我怎样才能显示在弹出窗口中正确的数据?