我有办法让一个表的列名。 它工作正常,但现在我想更新到新的mysqli? (我试过mysqli_fetch_field,但我不知道如何适用于这种情况下,我不知道这是否是莱特选项)
如何做相同的mysqli的? :
$sql = "SELECT * from myTable";
$result = mysql_query($sql,$con);
$id = mysql_field_name($result, 0);
$a = mysql_field_name($result, 1);
echo $id;
echo $a;
这是实现这个功能缺失的方式:
function mysqli_field_name($result, $field_offset)
{
$properties = mysqli_fetch_field_direct($result, $field_offset);
return is_object($properties) ? $properties->name : null;
}
我不知道是否有更好的方式来做到这一点,但我检查了这部作品获得列的仅仅是名字,是新的mysqli:
$result = mysqli_query($con, 'SELECT * FROM myTable');
while ($property = mysqli_fetch_field($result)) {
echo $property->name;
}
您可以替换功能mysql_field_name
到mysqli_fetch_field_direct
并使用它像下面这样:
$colObj = mysqli_fetch_field_direct($result,$i);
$col = $colObj->name;
echo "<br/>Coluna: ".$col;
这是打印每个字段的名称,表中的另一个简单的方法,和最大长度
$sql="SELECT Lastname,Age FROM Persons ORDER BY Lastname";
if ($result=mysqli_query($con,$sql))
{
// Get field information for all fields
while ($fieldinfo=mysqli_fetch_field($result))
{
printf("Name: %s\n",$fieldinfo->name);
printf("Table: %s\n",$fieldinfo->table);
printf("max. Len: %d\n",$fieldinfo->max_length);
}
// Free result set
mysqli_free_result($result);
}
$sql = "SELECT * from myTable";
$res = mysqli_query($con,$sql);
$row = mysqli_fetch_assoc($res);
$fields = array_keys($row);
var_dump($fields);