如何创建SQL Server中的支点查询，而聚合函数(How to create a pivot q

我使用的MS SQL Server 2008和我有以下数据：

select * from account;

| PERIOD | ACCOUNT | VALUE |
----------------------------
|   2000 |   Asset |   205 |
|   2000 |  Equity |   365 |
|   2000 |  Profit |   524 |
|   2001 |   Asset |   142 |
|   2001 |  Equity |   214 |
|   2001 |  Profit |   421 |
|   2002 |   Asset |   421 |
|   2002 |  Equity |   163 |
|   2002 |  Profit |   325 |

我想让他们是这样的：

| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
|   Asset |  205 |  142 |  421 |
|  Equity |  365 |  214 |  163 |
|  Profit |  524 |  421 |  325 |

我试着查询使用pivot query ，但值必须使用aggregate function ，结果是不恰当的。 我该怎么办？

Answer 1:

SELECT *
FROM
(
SELECT [Period], [Account], [Value]
FROM TableName
) AS source
PIVOT
(
    MAX([Value])
    FOR [Period] IN ([2000], [2001], [2002])
) as pvt

其他方式，

SELECT ACCOUNT,
      MAX(CASE WHEN Period = '2000' THEN Value ELSE NULL END) [2000],
      MAX(CASE WHEN Period = '2001' THEN Value ELSE NULL END) [2001],
      MAX(CASE WHEN Period = '2002' THEN Value ELSE NULL END) [2002]
FROM tableName
GROUP BY Account

• SQLFiddle演示（ 包括查询 ）

Answer 2:

检查了这一点还有：使用xml path和pivot

SQLFIDDLE DEMO

| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
|   Asset |  205 |  142 |  421 |
|  Equity |  365 |  214 |  163 |
|  Profit |  524 |  421 |  325 |

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

SET @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.period) 
            FROM demo c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT account, ' + @cols + ' from 
            (
                select account
                    , value
                    , period
                from demo
           ) x
            pivot 
            (
                 max(value)
                for period in (' + @cols + ')
            ) p '


execute(@query)

文章来源: How to create a pivot query in sql server without aggregate function