可以String.Format()
在VB6中实现,至少它的足够接近的版本,在良好的醇编程” VB6的时候可能是有用的?
对VB6字符串处理性能再好的资源: http://www.aivosto.com/vbtips/stringopt2.html
与此相关的不,我也来了一对夫妇的字符串比较功能,发现他们在这里CodeReview.SE
这些功能对于改善VB6可读性相当有用的,特别是如果你最近一直宠坏.NET代码,突然被要求潜入VB6的代码库...享受!
可以String.Format()
在VB6中实现,至少它的足够接近的版本,在良好的醇编程” VB6的时候可能是有用的?
对VB6字符串处理性能再好的资源: http://www.aivosto.com/vbtips/stringopt2.html
与此相关的不,我也来了一对夫妇的字符串比较功能,发现他们在这里CodeReview.SE
这些功能对于改善VB6可读性相当有用的,特别是如果你最近一直宠坏.NET代码,突然被要求潜入VB6的代码库...享受!
我找不到任何地方一个,所以我做了我自己的:
Public PADDING_CHAR As String
Public Function StringFormat(format_string As String, ParamArray values()) As String
'VB6 implementation of .net String.Format(), slightly customized.
'Tested with Office 2010 VBA (x64)
Dim return_value As String
Dim values_count As Integer
'some error-handling constants:
Const ERR_FORMAT_EXCEPTION As Long = vbObjectError Or 9001
Const ERR_ARGUMENT_NULL_EXCEPTION As Long = vbObjectError Or 9002
Const ERR_SOURCE As String = "StringFormat"
Const ERR_MSG_INVALID_FORMAT_STRING As String = "Invalid format string."
Const ERR_MSG_FORMAT_EXCEPTION As String = "The number indicating an argument to format is less than zero, or greater than or equal to the length of the args array."
'use SPACE as default padding character
If PADDING_CHAR = vbNullString Then PADDING_CHAR = Chr$(32)
'figure out number of passed values:
values_count = UBound(values) + 1
Dim regex As RegExp
Dim matches As MatchCollection
Dim thisMatch As Match
Dim thisString As String
Dim thisFormat As String
'when format_string starts with "@", escapes are not replaced
'(string is treated as a literal string with placeholders)
Dim useLiteral As Boolean
Dim escapeHex As Boolean 'indicates whether HEX specifier "0x" is to be escaped or not
'validate string_format:
Set regex = New RegExp
regex.Pattern = "{({{)*(\w+)(,-?\d+)?(:[^}]+)?}(}})*"
regex.IgnoreCase = True
regex.Global = True
Set matches = regex.Execute(format_string)
'determine if values_count matches number of unique regex matches:
Dim uniqueCount As Integer
Dim tmpCSV As String
For Each thisMatch In matches
If Not StringContains(tmpCSV, thisMatch.SubMatches(1)) Then
uniqueCount = uniqueCount + 1
tmpCSV = tmpCSV & thisMatch.SubMatches(1) & ","
End If
Next
'unique indices count must match values_count:
If matches.Count > 0 And uniqueCount <> values_count Then _
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_FORMAT_EXCEPTION
useLiteral = StringStartsWith("@", format_string)
'remove the "@" literal specifier
If useLiteral Then format_string = Right(format_string, Len(format_string) - 1)
If Not useLiteral And StringContains(format_string, "\\") Then _
format_string = Replace(format_string, "\\", Chr$(27))
If StringContains(format_string, "\\") Then _
format_string = Replace(format_string, "\\", Chr$(27))
If matches.Count = 0 And format_string <> vbNullString And UBound(values) = -1 Then
'only format_string was specified: skip to checking escape sequences:
return_value = format_string
GoTo checkEscapes
ElseIf UBound(values) = -1 And matches.Count > 0 Then
Err.Raise ERR_ARGUMENT_NULL_EXCEPTION, _
ERR_SOURCE, ERR_MSG_FORMAT_EXCEPTION
End If
return_value = format_string
'dissect format_string:
Dim i As Integer, v As String, p As String 'i: iterator; v: value; p: placeholder
Dim alignmentGroup As String, alignmentSpecifier As String
Dim formattedValue As String, alignmentPadding As Integer
'iterate regex matches (each match is a placeholder):
For i = 0 To matches.Count - 1
'get the placeholder specified index:
Set thisMatch = matches(i)
p = thisMatch.SubMatches(1)
'if specified index (0-based) > uniqueCount (1-based), something's wrong:
If p > uniqueCount - 1 Then _
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_FORMAT_EXCEPTION
v = values(p)
'get the alignment specifier if it is specified:
alignmentGroup = thisMatch.SubMatches(2)
If alignmentGroup <> vbNullString Then _
alignmentSpecifier = Right$(alignmentGroup, LenB(alignmentGroup) / 2 - 1)
'get the format specifier if it is specified:
thisString = thisMatch.Value
If StringContains(thisString, ":") Then
Dim formatGroup As String, precisionSpecifier As Integer
Dim formatSpecifier As String, precisionString As String
'get the string between ":" and "}":
formatGroup = Mid$(thisString, InStr(1, thisString, ":") + 1, (LenB(thisString) / 2) - 2)
formatGroup = Left$(formatGroup, LenB(formatGroup) / 2 - 1)
precisionString = Right$(formatGroup, LenB(formatGroup) / 2 - 1)
formatSpecifier = Mid$(thisString, InStr(1, thisString, ":") + 1, 1)
'applicable formatting depends on the type of the value (yes, GOTO!!):
If TypeName(values(p)) = "Date" Then GoTo DateTimeFormatSpecifiers
If v = vbNullString Then GoTo ApplyStringFormat
NumberFormatSpecifiers:
If precisionString <> vbNullString And Not IsNumeric(precisionString) Then _
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_INVALID_FORMAT_STRING
If precisionString = vbNullString Then precisionString = 0
Select Case formatSpecifier
Case "C", "c" 'CURRENCY format, formats string as currency.
'Precision specifier determines number of decimal digits.
'This implementation ignores regional settings
'(hard-coded group separator, decimal separator and currency sign).
precisionSpecifier = CInt(precisionString)
thisFormat = "#,##0.$"
If LenB(formatGroup) > 2 And precisionSpecifier > 0 Then
'if a non-zero precision is specified...
thisFormat = _
Replace$(thisFormat, ".", "." & String$(precisionString, Chr$(48)))
End If
Case "D", "d" 'DECIMAL format, formats string as integer number.
'Precision specifier determines number of digits in returned string.
precisionSpecifier = CInt(precisionString)
thisFormat = "0"
thisFormat = Right$(String$(precisionSpecifier, "0") & thisFormat, _
IIf(precisionSpecifier = 0, Len(thisFormat), precisionSpecifier))
Case "E", "e" 'EXPONENTIAL NOTATION format (aka "Scientific Notation")
'Precision specifier determines number of decimals in returned string.
'This implementation ignores regional settings'
'(hard-coded decimal separator).
precisionSpecifier = CInt(precisionString)
thisFormat = "0.00000#" & formatSpecifier & "-#" 'defaults to 6 decimals
If LenB(formatGroup) > 2 And precisionSpecifier > 0 Then
'if a non-zero precision is specified...
thisFormat = "0." & String$(precisionSpecifier - 1, Chr$(48)) & "#" & formatSpecifier & "-#"
ElseIf LenB(formatGroup) > 2 And precisionSpecifier = 0 Then
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_INVALID_FORMAT_STRING
End If
Case "F", "f" 'FIXED-POINT format
'Precision specifier determines number of decimals in returned string.
'This implementation ignores regional settings'
'(hard-coded decimal separator).
precisionSpecifier = CInt(precisionString)
thisFormat = "0"
If LenB(formatGroup) > 2 And precisionSpecifier > 0 Then
'if a non-zero precision is specified...
thisFormat = (thisFormat & ".") & String$(precisionSpecifier, Chr$(48))
Else
'no precision specified - default to 2 decimals:
thisFormat = "0.00"
End If
Case "G", "g" 'GENERAL format (recursive)
'returns the shortest of either FIXED-POINT or SCIENTIFIC formats in case of a Double.
'returns DECIMAL format in case of a Integer or Long.
Dim eNotation As String, ePower As Integer, specifier As String
precisionSpecifier = IIf(CInt(precisionString) > 0, CInt(precisionString), _
IIf(StringContains(v, "."), Len(v) - InStr(1, v, "."), 0))
'track character case of formatSpecifier:
specifier = IIf(formatSpecifier = "G", "D", "d")
If TypeName(values(p)) = "Integer" Or TypeName(values(p)) = "Long" Then
'Integer types: use {0:D} (recursive call):
formattedValue = StringFormat("{0:" & specifier & "}", values(p))
ElseIf TypeName(values(p)) = "Double" Then
'Non-integer types: use {0:E}
specifier = IIf(formatSpecifier = "G", "E", "e")
'evaluate the exponential notation value (recursive call):
eNotation = StringFormat("{0:" & specifier & "}", v)
'get the power of eNotation:
ePower = Mid$(eNotation, InStr(1, UCase$(eNotation), "E-") + 1, Len(eNotation) - InStr(1, UCase$(eNotation), "E-"))
If ePower > -5 And Abs(ePower) < precisionSpecifier Then
'use {0:F} when ePower > -5 and abs(ePower) < precisionSpecifier:
'evaluate the floating-point value (recursive call):
specifier = IIf(formatSpecifier = "G", "F", "f")
formattedValue = StringFormat("{0:" & formatSpecifier & _
IIf(precisionSpecifier <> 0, precisionString, vbNullString) & "}", values(p))
Else
'fallback to {0:E} if previous rule didn't apply:
formattedValue = eNotation
End If
End If
GoTo AlignFormattedValue 'Skip the "ApplyStringFormat" step, it's applied already.
Case "N", "n" 'NUMERIC format, formats string as an integer or decimal number.
'Precision specifier determines number of decimal digits.
'This implementation ignores regional settings'
'(hard-coded group and decimal separators).
precisionSpecifier = CInt(precisionString)
If LenB(formatGroup) > 2 And precisionSpecifier > 0 Then
'if a non-zero precision is specified...
thisFormat = "#,##0"
thisFormat = (thisFormat & ".") & String$(precisionSpecifier, Chr$(48))
Else 'only the "D" is specified
thisFormat = "#,##0"
End If
Case "P", "p" 'PERCENT format. Formats string as a percentage.
'Value is multiplied by 100 and displayed with a percent symbol.
'Precision specifier determines number of decimal digits.
thisFormat = "#,##0%"
precisionSpecifier = CInt(precisionString)
If LenB(formatGroup) > 2 And precisionSpecifier > 0 Then
'if a non-zero precision is specified...
thisFormat = "#,##0"
thisFormat = (thisFormat & ".") & String$(precisionSpecifier, Chr$(48))
Else 'only the "P" is specified
thisFormat = "#,##0"
End If
'Append the percentage sign to the format string:
thisFormat = thisFormat & "%"
Case "R", "r" 'ROUND-TRIP format (a string that can round-trip to an identical number)
'example: ?StringFormat("{0:R}", 0.0000000001141596325677345362656)
' ...returns "0.000000000114159632567735"
'convert value to a Double (chop off overflow digits):
v = CDbl(v)
Case "X", "x" 'HEX format. Formats a string as a Hexadecimal value.
'Precision specifier determines number of total digits.
'Returned string is prefixed with "&H" to specify Hex.
v = Hex(v)
precisionSpecifier = CInt(precisionString)
If LenB(precisionString) > 0 Then 'precision here stands for left padding
v = Right$(String$(precisionSpecifier, "0") & v, IIf(precisionSpecifier = 0, Len(v), precisionSpecifier))
End If
'add C# hex specifier, apply specified casing:
'(VB6 hex specifier would cause Format() to reverse the formatting):
v = "0x" & IIf(formatSpecifier = "X", UCase$(v), LCase$(v))
Case Else
If IsNumeric(formatSpecifier) And val(formatGroup) = 0 Then
formatSpecifier = formatGroup
v = Format(v, formatGroup)
Else
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_INVALID_FORMAT_STRING
End If
End Select
GoTo ApplyStringFormat
DateTimeFormatSpecifiers:
Select Case formatSpecifier
Case "c", "C" 'CUSTOM date/time format
'let VB Format() parse precision specifier as is:
thisFormat = precisionString
Case "d" 'SHORT DATE format
thisFormat = "ddddd"
Case "D" 'LONG DATE format
thisFormat = "dddddd"
Case "f" 'FULL DATE format (short)
thisFormat = "dddddd h:mm AM/PM"
Case "F" 'FULL DATE format (long)
thisFormat = "dddddd ttttt"
Case "g"
thisFormat = "ddddd hh:mm AM/PM"
Case "G"
thisFormat = "ddddd ttttt"
Case "s" 'SORTABLE DATETIME format
thisFormat = "yyyy-mm-ddThh:mm:ss"
Case "t" 'SHORT TIME format
thisFormat = "hh:mm AM/PM"
Case "T" 'LONG TIME format
thisFormat = "ttttt"
Case Else
Err.Raise ERR_FORMAT_EXCEPTION, _
ERR_SOURCE, ERR_MSG_INVALID_FORMAT_STRING
End Select
GoTo ApplyStringFormat
End If
ApplyStringFormat:
'apply computed format string:
formattedValue = Format(v, thisFormat)
AlignFormattedValue:
'apply specified alignment specifier:
If alignmentSpecifier <> vbNullString Then
alignmentPadding = Abs(CInt(alignmentSpecifier))
If CInt(alignmentSpecifier) < 0 Then
'negative: left-justified alignment
If alignmentPadding - Len(formattedValue) > 0 Then _
formattedValue = formattedValue & _
String$(alignmentPadding - Len(formattedValue), PADDING_CHAR)
Else
'positive: right-justified alignment
If alignmentPadding - Len(formattedValue) > 0 Then _
formattedValue = String$(alignmentPadding - Len(formattedValue), PADDING_CHAR) & formattedValue
End If
End If
'Replace C# hex specifier with VB6 hex specifier,
'only if hex specifier was introduced in this function:
If (Not useLiteral And escapeHex) And _
StringContains(formattedValue, "0x") Then _
formattedValue = Replace$(formattedValue, "0x", "&H")
'replace all occurrences of placeholder {i} with their formatted values:
return_value = Replace(return_value, thisString, formattedValue, Count:=1)
'reset before reiterating:
thisFormat = vbNullString
Next
checkEscapes:
'if there's no more backslashes, don't bother checking for the rest:
If useLiteral Or Not StringContains(return_value, "\") Then GoTo normalExit
Dim escape As New EscapeSequence
Dim escapes As New Collection
escapes.Add escape.Create("\n", vbNewLine), "0"
escapes.Add escape.Create("\q", Chr$(34)), "1"
escapes.Add escape.Create("\t", vbTab), "2"
escapes.Add escape.Create("\a", Chr$(7)), "3"
escapes.Add escape.Create("\b", Chr$(8)), "4"
escapes.Add escape.Create("\v", Chr$(13)), "5"
escapes.Add escape.Create("\f", Chr$(14)), "6"
escapes.Add escape.Create("\r", Chr$(15)), "7"
For i = 0 To escapes.Count - 1
Set escape = escapes(CStr(i))
If StringContains(return_value, escape.EscapeString) Then _
return_value = Replace(return_value, escape.EscapeString, escape.ReplacementString)
If Not StringContains(return_value, "\") Then _
GoTo normalExit
Next
'replace "ASCII (oct)" escape sequence
Set regex = New RegExp
regex.Pattern = "\\(\d{3})"
regex.IgnoreCase = True
regex.Global = True
Set matches = regex.Execute(format_string)
Dim char As Long
If matches.Count <> 0 Then
For Each thisMatch In matches
p = thisMatch.SubMatches(0)
'"p" contains the octal number representing the ASCII code we're after:
p = "&O" & p 'prepend octal prefix
char = CLng(p)
return_value = Replace(return_value, thisMatch.Value, Chr$(char))
Next
End If
'if there's no more backslashes, don't bother checking for the rest:
If Not StringContains("\", return_value) Then GoTo normalExit
'replace "ASCII (hex)" escape sequence
Set regex = New RegExp
regex.Pattern = "\\x(\w{2})"
regex.IgnoreCase = True
regex.Global = True
Set matches = regex.Execute(format_string)
If matches.Count <> 0 Then
For Each thisMatch In matches
p = thisMatch.SubMatches(0)
'"p" contains the hex value representing the ASCII code we're after:
p = "&H" & p 'prepend hex prefix
char = CLng(p)
return_value = Replace(return_value, thisMatch.Value, Chr$(char))
Next
End If
normalExit:
Set escapes = Nothing
Set escape = Nothing
If Not useLiteral And StringContains(return_value, Chr$(27)) Then _
return_value = Replace(return_value, Chr$(27), "\")
StringFormat = return_value
End Function
注意ParamArray
方法签名(感谢@wqw):这样做备件的多个可选参数的使用(和使用漏洞与能够分配value2
不分配value1
的调用语句命名参数时)。 因为它是一个ParamArray
,个体值是Variant
,这意味着每一个参数可以是不同类型的,VB是做幕后的字符串转换。
这时可把功能消耗是这样的:
?StringFormat("(C) Currency: . . . . . . . . {0:C}\n" & _
"(D) Decimal:. . . . . . . . . {0:D}\n" & _
"(E) Scientific: . . . . . . . {1:E}\n" & _
"(F) Fixed point:. . . . . . . {1:F}\n" & _
"(N) Number: . . . . . . . . . {0:N}\n" & _
"(P) Percent:. . . . . . . . . {1:P}\n" & _
"(R) Round-trip: . . . . . . . {1:R}\n" & _
"(X) Hexadecimal:. . . . . . . {0:X}\n",-123, -123.45)
输出:
(C) Currency: . . . . . . . . -123.00$
(D) Decimal:. . . . . . . . . -123
(E) Scientific: . . . . . . . -1.23450E2
(F) Fixed point:. . . . . . . -123
(N) Number: . . . . . . . . . -123
(P) Percent:. . . . . . . . . -12,345%
(R) Round-trip: . . . . . . . -123.45
(X) Hexadecimal:. . . . . . . &HFFFFFF85
而且也很喜欢这一点:
?StringFormat("(c) Custom format: . . . . . .{0:cYYYY-MM-DD (MMMM)}\n" & _
"(d) Short date: . . . . . . . {0:d}\n" & _
"(D) Long date:. . . . . . . . {0:D}\n" & _
"(T) Long time:. . . . . . . . {0:T}\n" & _
"(f) Full date/short time: . . {0:f}\n" & _
"(F) Full date/long time:. . . {0:F}\n" & _
"(s) Sortable: . . . . . . . . {0:s}\n", Now())
输出:
(c) Custom format: . . . . . .2013-01-26 (January)
(d) Short date: . . . . . . . 1/26/2013
(D) Long date:. . . . . . . . Saturday, January 26, 2013
(T) Long time:. . . . . . . . 8:28:11 PM
(f) Full date/short time: . . 1/26/2013 8:28:11 PM
(F) Full date/long time:. . . Saturday, January 26, 2013 8:28:11 PM
(s) Sortable: . . . . . . . . 2013-01-26T20:28:11
还可以指定对准(/填充),并使用转义序列:
?StringFormat ("\q{0}, {1}!\x20\n'{2,10:C2}'\n'{2,-10:C2}'", "hello", "world", 100)
"hello, world!"
' 100.00$'
'100.00$ '
看着从样品http://msdn.microsoft.com/fr-fr/library/b1csw23d(v=vs.80).aspx ,只有少数格式说明没有实现,主要是日期/时间说明符...但我会认为“C”自定义日期/时间格式说明符使得它。
该函数使用一个简单的实施String.Contains()
Public Function StringContains(string_source As String, find_text As String, _
Optional ByVal caseSensitive As Boolean = True) As Boolean
StringContains = StringContainsAny(string_source, caseSensitive, find_text)
End Function
编辑:该代码可以正确处理“\\”逃脱,如在评论中提到。 此外,虽然StringContains
肯定是实用的,并给出了更舒适的阅读比InStr()
调用,下面StringContainsAny
功能,甚至更好:
Public Function StringContainsAny(string_source As String, ByVal caseSensitive As Boolean, _
ParamArray find_values()) As Boolean
Dim i As Integer, found As Boolean
If caseSensitive Then
For i = LBound(find_values) To UBound(find_values)
found = (InStr(1, string_source, _
find_values(i), vbBinaryCompare) <> 0)
If found Then Exit For
Next
Else
For i = LBound(find_values) To UBound(find_values)
StringContainsAny = (InStr(1, LCase$(string_source), _
LCase$(find_values(i)), vbBinaryCompare) <> 0)
If found Then Exit For
Next
End If
StringContainsAny = found
End Function
考虑以下:
foo = Instr(1, source, "value1") > 0 Or Instr(1, source, "value2") > 0 _
Or Instr(1, source, "value3") > 0 Or Instr(1, source, "value4") > 0 _
Or Instr(1, source, "value5") > 0 Or Instr(1, source, "value6") > 0 _
之前VB可确定是否foo
为TRUE
或FALSE
,每一个InStr()
调用。 然而,随着StringContainsAny()
满足条件时与被发现的第一个值,这使得它更快的声明。
编辑:上编辑几乎全军覆没转义序列; 恢复他们,用小班“EscapeSequence”暴露两个属性和一个工厂方法 - 这样做可以保持for-each循环和处理所有简单的逃脱,而无需复制大量代码。
此代码还使用了StringStartsWith
功能,这样实现的:
Public Function StringStartsWith(ByVal find_text As String, ByVal string_source As String, Optional ByVal caseSensitive As Boolean = True) As Boolean
If caseSensitive Then
StringStartsWith = (Left$(string_source, LenB(find_text) / 2) = find_text)
Else
StringStartsWith = (Left$(LCase(string_source), LenB(find_text) / 2) = LCase$(find_text))
End If
End Function