做一个Android的TextView中的某一部分右对齐(Make a certain part o

我有这样TextView 。它的某些部分是应该左对齐和某些部分的权利。我将如何在Java中做到这一点？

Basicly我想的第一行对齐到左边，下一行的权利等。

任何人都得到了线索？

编辑

我曾尝试使用HTML，然后当没有工作，我试图跨越。

HTML尝试

textView.setText(Html.fromHtml("<p align=\"right\">THIS IS TO THE RIGHT</p>"));

和继承人的跨度尝试

    String LeftText = "LEFT";
    String RightText = "RIGHT";

    final String resultText = LeftText + "  " + RightText;
    final SpannableString styledResultText = new SpannableString(resultText);
    styledResultText.setSpan(new AlignmentSpan.Standard(Alignment.ALIGN_OPPOSITE), LeftText.length() + 1, LeftText.length() + 2 +RightText.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
    textView.setText(styledResultText);

但他们都不似乎工作。

Answer 1:

TextView resultTextView = new TextView(this);
final String resultText = LeftText + "  " + RightText;
final SpannableString styledResultText = new SpannableString(resultText);
styledResultText.setSpan(new AlignmentSpan.Standard(Alignment.ALIGN_OPPOSITE)
    , LeftText.length() + 2
    , LeftText.length() + 2 + RightText.length()
    , Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
resultTextView.setText(styledResultText);

Alignment.ALIGN_OPPOSITE is the equivalent for right side.

Alignment.ALIGN_NORMAL is the equivalent for left side.

Answer 2:

下面是与Spannable工作，与cavate，如果左，右太宽，他们将在同一行重叠的解决方案。既然做了左/右招用spannable需要左和右之间的换行，我的解决办法是增加，减少行高度为零spannable（即重叠线）为一个换行，然后恢复后正常的行高那。

    String fullText = leftText + "\n " + rightText;     // only works if  linefeed between them! "\n ";

    int fullTextLength = fullText.length();
    int leftEnd = leftText.length();
    int rightTextLength = rightText.length();

    final SpannableString s = new SpannableString(fullText);
    AlignmentSpan alignmentSpan = new AlignmentSpan.Standard(Layout.Alignment.ALIGN_OPPOSITE);
    s.setSpan(alignmentSpan, leftEnd, fullTextLength, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
    s.setSpan(new SetLineOverlap(true), 1, fullTextLength-2, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
    s.setSpan(new SetLineOverlap(false), fullTextLength-1, fullTextLength, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);

而我们的小程序来处理重叠的线路：

    private static class SetLineOverlap implements LineHeightSpan {
    private int originalBottom = 15;        // init value ignored
    private int originalDescent = 13;       // init value ignored
    private Boolean overlap;                // saved state
    private Boolean overlapSaved = false;   // ensure saved values only happen once

    SetLineOverlap(Boolean overlap) {
        this.overlap = overlap;
    }

    @Override
    public void chooseHeight(CharSequence text, int start, int end, int spanstartv, int v,
                             Paint.FontMetricsInt fm) {
        if (overlap) {
            if (!overlapSaved) {
                originalBottom = fm.bottom;
                originalDescent = fm.descent;
                overlapSaved = true;
            }
            fm.bottom += fm.top;
            fm.descent += fm.top;
        } else {
            // restore saved values
            fm.bottom = originalBottom;
            fm.descent = originalDescent;
            overlapSaved = false;
        }
    }
}

Answer 3:

谢谢你的提示，@Frank，但这只是不够：

public class LineOverlapSpan implements LineHeightSpan {
    @Override
    public void chooseHeight(final CharSequence text, final int start, final int end, final int spanstartv, final int v, final Paint.FontMetricsInt fm) {
        fm.bottom += fm.top;
        fm.descent += fm.top;
    }
}

使用这样的：

CharSequence text = return new Truss()
        .append("LEFT")
        .pushSpan(LineOverlapSpan())
        .append("\n")
        .popSpan()
        .pushSpan(AlignmentSpan.Standard(Layout.Alignment.ALIGN_OPPOSITE))
        .append("RIGHT")
        .build()

其中Truss是