这个问题已经在这里有一个答案:
- 在SQL转换数目字[复制] 2个回答
是否有任何疑问或功能可以在任何没有转换成单词。 喜欢1001到我使用SQL Server 2005的一千等。
这个问题已经在这里有一个答案:
是否有任何疑问或功能可以在任何没有转换成单词。 喜欢1001到我使用SQL Server 2005的一千等。
喜试试下面PROC ....它给你所需要的输出....
步骤:
CREATE FUNCTION fnNumberToWords(@Number as BIGINT)
RETURNS VARCHAR(1024)
AS
BEGIN
DECLARE @Below20 TABLE (ID int identity(0,1), Word varchar(32))
DECLARE @Below100 TABLE (ID int identity(2,1), Word varchar(32))
INSERT @Below20 (Word) VALUES
( 'Zero'), ('One'),( 'Two' ), ( 'Three'),
( 'Four' ), ( 'Five' ), ( 'Six' ), ( 'Seven' ),
( 'Eight'), ( 'Nine'), ( 'Ten'), ( 'Eleven' ),
( 'Twelve' ), ( 'Thirteen' ), ( 'Fourteen'),
( 'Fifteen' ), ('Sixteen' ), ( 'Seventeen'),
('Eighteen' ), ( 'Nineteen' )
INSERT @Below100 VALUES ('Twenty'), ('Thirty'),('Forty'), ('Fifty'),
('Sixty'), ('Seventy'), ('Eighty'), ('Ninety')
DECLARE @English varchar(1024) =
(
SELECT Case
WHEN @Number = 0 THEN ''
WHEN @Number BETWEEN 1 AND 19
THEN (SELECT Word FROM @Below20 WHERE ID=@Number)
WHEN @Number BETWEEN 20 AND 99
THEN (SELECT Word FROM @Below100 WHERE ID=@Number/10)+ '-' +
dbo.fnNumberToWords( @Number % 10)
WHEN @Number BETWEEN 100 AND 999
THEN (dbo.fnNumberToWords( @Number / 100))+' Hundred '+
dbo.fnNumberToWords( @Number % 100)
WHEN @Number BETWEEN 1000 AND 999999
THEN (dbo.fnNumberToWords( @Number / 1000))+' Thousand '+
dbo.fnNumberToWords( @Number % 1000)
WHEN @Number BETWEEN 1000000 AND 999999999
THEN (dbo.fnNumberToWords( @Number / 1000000))+' Million '+
dbo.fnNumberToWords( @Number % 1000000)
WHEN @Number BETWEEN 1000000000 AND 999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000))+' Billion '+
dbo.fnNumberToWords( @Number % 1000000000)
WHEN @Number BETWEEN 1000000000000 AND 999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000))+' Trillion '+
dbo.fnNumberToWords( @Number % 1000000000000)
WHEN @Number BETWEEN 1000000000000000 AND 999999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000000))+' Quadrillion '+
dbo.fnNumberToWords( @Number % 1000000000000000)
WHEN @Number BETWEEN 1000000000000000000 AND 999999999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000000000))+' Quintillion '+
dbo.fnNumberToWords( @Number % 1000000000000000000)
ELSE ' INVALID INPUT' END
)
SELECT @English = RTRIM(@English)
SELECT @English = RTRIM(LEFT(@English,len(@English)-1))
WHERE RIGHT(@English,1)='-'
RETURN (@English)
END
GO
测试查询.....
SELECT NumberInEnglish=dbo.fnNumberToWords ( 18)
SELECT NumberInEnglish=dbo.fnNumberToWords ( 67)
SELECT NumberInEnglish=dbo.fnNumberToWords ( 947)
-- Nine Hundred Forty-Seven
SELECT NumberInEnglish=dbo.fnNumberToWords ( 984261)
-- Nine Hundred Eighty-Four Thousand Two Hundred Sixty-One
SELECT NumberInEnglish=dbo.fnNumberToWords ( 777999888)
/* Seven Hundred Seventy-Seven Million Nine Hundred Ninety-Nine Thousand
Eight Hundred Eighty-Eight */
SELECT NumberInEnglish=dbo.fnNumberToWords ( 222777999888)
SELECT NumberInEnglish=dbo.fnNumberToWords ( 555222777999888)
SELECT NumberInEnglish=dbo.fnNumberToWords ( 7446744073709551616)
资料来源: http://www.sqlusa.com/bestpractices2008/number-to-words/
你可以试试这个工作在甲骨文:
select to_char(to_date(:number,'j'),'jsp') from dual;
或者看到这里再怎么做了一个详细的链接
有没有这样的查询。 你需要创建自己的程序,然后你可以使用它。