使用jQuery从海量文本中提取的所有电子邮件地址(Extract all email addres

我在下面这段文字：

sdabhikagathara@rediffmail.com, "assdsdf" <dsfassdfhsdfarkal@gmail.com>, "rodnsdfald ferdfnson" <rfernsdfson@gmail.com>, "Affdmdol Gondfgale" <gyfanamosl@gmail.com>, "truform techno" <pidfpinfg@truformdftechnoproducts.com>, "NiTsdfeSh ThIdfsKaRe" <nthfsskare@ysahoo.in>, "akasdfsh kasdfstla" <akashkatsdfsa@yahsdfsfoo.in>, "Bisdsdfamal Prakaasdsh" <bimsdaalprakash@live.com>,; "milisdfsfnd ansdfasdfnsftwar" <dfdmilifsd.ensfdfcogndfdfatia@gmail.com>

这里的电子邮件是由seprated ,或; 。我想提取存在的所有邮件上面，并将它们存储在阵列。有没有使用正则表达式来直接获取所有的电子邮件没有简单的方法？

Answer 1:

这里是你如何处理这个：

HTML

<p id="emails"></p>

JavaScript的

var text = 'sdabhikagathara@rediffmail.com, "assdsdf" <dsfassdfhsdfarkal@gmail.com>, "rodnsdfald ferdfnson" <rfernsdfson@gmal.com>, "Affdmdol Gondfgale" <gyfanamosl@gmail.com>, "truform techno" <pidfpinfg@truformdftechnoproducts.com>, "NiTsdfeSh ThIdfsKaRe" <nthfsskare@ysahoo.in>, "akasdfsh kasdfstla" <akashkatsdfsa@yahsdfsfoo.in>, "Bisdsdfamal Prakaasdsh" <bimsdaalprakash@live.com>,; "milisdfsfnd ansdfasdfnsftwar" <dfdmilifsd.ensfdfcogndfdfatia@gmail.com>';    

function extractEmails (text)
{
    return text.match(/([a-zA-Z0-9._-]+@[a-zA-Z0-9._-]+\.[a-zA-Z0-9._-]+)/gi);
}

$("#emails").text(extractEmails(text).join('\n'));

结果

sdabhikagathara@rediffmail.com dsfassdfhsdfarkal@gmail.com rfernsdfson@gmal.com gyfanamosl@gmail.com pidfpinfg@truformdftechnoproducts.com nthfsskare@ysahoo.in akashkatsdfsa@yahsdfsfoo.in bimsdaalprakash@live.com dfdmilifsd.ensfdfcogndfdfatia@gmail.com

来源：从批量文本中提取电子邮件（正则表达式，JavaScript的和jQuery的）

演示1在这里

演示2这里使用jQuery的每个迭代器功能

Answer 2:

你可以使用这个表达式：

var re = /(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))/g;

您可以提取电子邮件是这样的：

('sdabhikagathara@rediffmail.com, "assdsdf" <dsfassdfhsdfarkal@gmail.com>, "rodnsdfald ferdfnson" <rfernsdfson@gmail.com>, "Affdmdol Gondfgale" <gyfanamosl@gmail.com>, "truform techno" <pidfpinfg@truformdftechnoproducts.com>, "NiTsdfeSh ThIdfsKaRe" <nthfsskare@ysahoo.in>, "akasdfsh kasdfstla" <akashkatsdfsa@yahsdfsfoo.in>, "Bisdsdfamal Prakaasdsh" <bimsdaalprakash@live.com>,; "milisdfsfnd ansdfasdfnsftwar" <dfdmilifsd.ensfdfcogndfdfatia@gmail.com>').match(re);

//["sdabhikagathara@rediffmail.com", "dsfassdfhsdfarkal@gmail.com", "rfernsdfson@gmail.com", "gyfanamosl@gmail.com", "pidfpinfg@truformdftechnoproducts.com", "nthfsskare@ysahoo.in", "akashkatsdfsa@yahsdfsfoo.in", "bimsdaalprakash@live.com", "dfdmilifsd.ensfdfcogndfdfatia@gmail.com"]

Answer 3:

只是一个更新接受的答案。这并不适用于在电子邮件地址“加”标志工作。 Gmail支持emailaddress+randomtext@gmail.com。

我已经更新到：

return text.match(/([a-zA-Z0-9._+-]+@[a-zA-Z0-9._-]+\.[a-zA-Z0-9._-]+)/gi);

Answer 4:

波纹管的功能是符合RFC2822根据Regexr.com

ES5：

var extract = function(value) {
   var reg = /[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?/g;
   return value && value.match(reg);
}

ES6：

const reg = /[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?/g
const extract = value => value && value.match(reg)

Regexr社区源

Answer 5:

function GetEmailsFromString(input) {
  var ret = [];
  var email = /\"([^\"]+)\"\s+\<([^\>]+)\>/g

  var match;
  while (match = email.exec(input))
    ret.push({'name':match[1], 'email':match[2]})

  return ret;
}

var str = '"Name one" <foo@domain.com>, ..., "And so on" <andsoon@gmx.net>'
var emails = GetEmailsFromString(str)

资源