2.0.1播放和设置访问控制允许来源(Play 2.0.1 and setting Access-C

我有一个播放2.0.1应用程序，我想使用Javascript托管在其他领域调用。 我的JavaScript调用与失败：

Origin http://mydomain.com is not allowed by Access-Control-Allow-Origin.

我已经发现了一些关于如何设置在播放1正确的HTTP标头的例子，但还没有找到播放2.0.1什么。 阅读文档后（http://www.playframework.org/documentation/2.0.2/JavaResponse）我试过只是把事情的工作如下：

public static Result myJsonWebService() {
  ...
  response().setHeader("Access-Control-Allow-Origin", "*");
  return ok(toJson(jsonObject));
}

但我的JS Web服务调用仍然失败。

我需要什么做的就是这个工作？

Answer 1:

只是为了Scala的家伙，这是我目前使用的实现：

import play.api.mvc._
import scala.concurrent._
import play.api.http.HeaderNames._

/**
 * Action decorator that provide CORS support
 *
 * @author Giovanni Costagliola, Nick McCready
 */
case class WithCors(httpVerbs: String*)(action: EssentialAction) extends EssentialAction with Results {
    def apply(request: RequestHeader) = {
        implicit val executionContext: ExecutionContext = play.api.libs.concurrent.Execution.defaultContext
        val origin = request.headers.get(ORIGIN).getOrElse("*")
        if (request.method == "OPTIONS") { // preflight
            val corsAction = Action {
                request =>
                    Ok("").withHeaders(
                        ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
                        ACCESS_CONTROL_ALLOW_METHODS -> (httpVerbs.toSet + "OPTIONS").mkString(", "),
                        ACCESS_CONTROL_MAX_AGE -> "3600",
                        ACCESS_CONTROL_ALLOW_HEADERS ->  s"$ORIGIN, X-Requested-With, $CONTENT_TYPE, $ACCEPT, $AUTHORIZATION, X-Auth-Token",
                        ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true")
            }
            corsAction(request)
        } else { // actual request
            action(request).map(res => res.withHeaders(
                ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
                ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
            ))
        }
    }
}

要使用它只是装饰用以下方式你的行动：

def myAction = WithCors("GET", "POST") {
  Action { request =>
    ???
  }
}

Answer 2:

下面是一些背景资料......

• 1）http://www.html5rocks.com/en/tutorials/cors/ - 请注意，你需要阅读一些关于“不那么简单的要求”为JSON属于这一类。
• 2）http://stackoverflow.com/questions/9613210/cors-access-control-allow-origin-despite-correct-headers?rq=1
• 3）http://caniuse.com/#search=cors - 详细的浏览器支持CORS
• 4）http://stackoverflow.com/questions/10748537/access-control-allow-origin-on-playframework（用于播放1 NOT播放2）

所以这是我实现的：

由于不那么简单的要求（见上文1）进行飞行前的通话，则需要以下内容添加到路由文件：

POST /url_to_json_webservice        controllers.myJsonWebServices.myJsonWebService
OPTIONS /url_to_json_webservice     controllers.myJsonWebServices.checkPreFlight

然后设置在控制器下面的方法：

public static Result checkPreFlight() {
    response().setHeader("Access-Control-Allow-Origin", "*");       // Need to add the correct domain in here!!
    response().setHeader("Access-Control-Allow-Methods", "POST");   // Only allow POST
    response().setHeader("Access-Control-Max-Age", "300");          // Cache response for 5 minutes
    response().setHeader("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");         // Ensure this header is also allowed!  
    return ok();
}

注意：我可能设置比这里需要更多的头部，所以请检查你需要哪些！

还记得添加以下到返回实际JSON结果（如上面我的问题）控制器方法的结尾：

public static Result myJsonWebService() {
  ...
  response().setHeader("Access-Control-Allow-Origin", "*");
  return ok(toJson(jsonObject));
}

Answer 3:

这样做的一个很好的方式是通过扩展操作：

package actions;

import play.*;
import play.mvc.*;
import play.mvc.Http.Context;
import play.mvc.Http.Response;

public class CorsAction extends Action.Simple {

public Result call(Context context) throws Throwable{
    Response response = context.response();
    response.setHeader("Access-Control-Allow-Origin", "*");

    //Handle preflight requests
    if(context.request().method().equals("OPTIONS")) {
        response.setHeader("Access-Control-Allow-Methods", "POST, GET, OPTIONS, PUT, DELETE");
        response.setHeader("Access-Control-Max-Age", "3600");
        response.setHeader("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept, Authorization, X-Auth-Token");
        response.setHeader("Access-Control-Allow-Credentials", "true");

        return ok();
    }

    response.setHeader("Access-Control-Allow-Headers","X-Requested-With, Content-Type, X-Auth-Token");
    return delegate.call(context);
}

}

然后在你的控制器中加入这一行：

@With(CorsAction.class)

然后，一切ok（）请求将上述标题回应。

Answer 4:

实现为斯卡拉过滤器（播放的2.2.x）：

import scala.concurrent.ExecutionContext.Implicits.global
import play.api.mvc._
import play.api.mvc.Results._
import play.api.http.HeaderNames._

object Cors extends Filter {
  def apply(next: (RequestHeader) => Future[SimpleResult])(request: RequestHeader): Future[SimpleResult] = {
    val origin = request.headers.get(ORIGIN).getOrElse("*")
    if (request.method == "OPTIONS") {
      val response = Ok.withHeaders(
        ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
        ACCESS_CONTROL_ALLOW_METHODS -> "POST, GET, OPTIONS, PUT, DELETE",
        ACCESS_CONTROL_MAX_AGE -> "3600",
        ACCESS_CONTROL_ALLOW_HEADERS -> s"$ORIGIN, X-Requested-With, $CONTENT_TYPE, $ACCEPT, $AUTHORIZATION, X-Auth-Token",
        ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
      )
      Future.successful(response)
    } else {
      next(request).map {
        res => res.withHeaders(
          ACCESS_CONTROL_ALLOW_ORIGIN -> origin,
          ACCESS_CONTROL_ALLOW_CREDENTIALS -> "true"
        )
      }
    }
  }
}

object Global extends WithFilters(Cors) {...}

文章来源: Play 2.0.1 and setting Access-Control-Allow-Origin