Xcode7 | Xcode UI Tests | How to handle location s

2019-01-13 10:42发布

问题:

I am writing UI Test Cases for one one of my app using the XCUIApplication, XCUIElement and XCUIElementQuery introduced in Xcode7/iOS 9.

I have hit a road block. One of the screens in test case requires iOS's Location Services. As expected the user is prompted about allowing use of location service with alert titled: Allow “App name” to access your location while you use the app? with Allow & Don't Allow buttons.

Problem is or so it seems that since the alert is presented by OS itself it is not present in Application's element sub-tree.

I have logged following:

print("XYZ:\(app.alerts.count)")//0
var existence = app.staticTexts["Allow “App Name” to access your location while you use the app?"].exists
print("XYZ:\(existence)")//false
existence  = app.buttons["Allow"].exists
print("XYZ:\(existence)") //false

Even UI recording generated similar code:

XCUIApplication().alerts["Allow “App Name” to access your location while you use the app?"].collectionViews.buttons["Allow"].tap()

I have not found any API that can get me past this problem. For example:

  • Tap at a position on the screen
  • Get alerts outside the app

So how can I get past this? Is there a way to configure Test Targets so that Location Service Authorization is not required.

回答1:

Xcode 9

    let springboard = XCUIApplication(bundleIdentifier: "com.apple.springboard")
    let allowBtn = springboard.buttons["Allow"]
    if allowBtn.exists {
        allowBtn.tap()
    }

Xcode 8.3.3

    _ = addUIInterruptionMonitor(withDescription: "Location Dialog") { (alert) -> Bool in
        alert.buttons["Allow"].tap()
        return true
    }
    app.buttons["Request Location"].tap()
    app.tap() // need to interact with the app for the handler to fire

Note that it is a bit different as the method name now is addUIInterruptionMonitor and takes withDescription as an argument

Xcode 7.1

Xcode 7.1 has finally fixed a issue with system alerts. There are, however, two small gotchas.

First, you need to set up a "UI Interuption Handler" before presenting the alert. This is our way of telling the framework how to handle an alert when it appears.

Second, after presenting the alert you must interact with the interface. Simply tapping the app works just fine, but is required.

addUIInterruptionMonitorWithDescription("Location Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

app.buttons["Request Location"].tap()
app.tap() // need to interact with the app for the handler to fire

The "Location Dialog" is just a string to help the developer identify which handler was accessed, it is not specific to the type of alert.

Xcode 7.0

The following will dismiss a single "system alert" in Xcode 7 Beta 6:

let app = XCUIApplication()
app.launch()
// trigger location permission dialog

app.alerts.element.collectionViews.buttons["Allow"].tap()

Beta 6 introduced a slew of fixes for UI Testing and I believe this was one of them.

Also note that I am calling -element directly on -alerts. Calling -element on an XCUIElementQuery forces the framework to choose the "one and only" matching element on the screen. This works great for alerts where you can only have one visible at a time. However, if you try this for a label and have two labels the framework will raise an exception.



回答2:

This was the only thing that worked for me. Using Xcode 9 fwiw.

Also probably relevant that I was already using addUIInterruptionMonitor for a different alert. I tried reordering them and it didn't make a difference. Could be that it's a problem in 9 when you have two, or could be I was using them wrong. In any event the code below worked. :)

let springboard = XCUIApplication(bundleIdentifier: "com.apple.springboard")
let allowBtn = springboard.buttons["Allow"]
if allowBtn.exists {
    allowBtn.tap()
}


回答3:

If you want to check if the alert is showing, just check for the existence of the button:

if (app.alerts.element.collectionViews.buttons["Dismiss"].exists)
{
app.alerts.element.collectionViews.buttons["Dismiss"].tap()
}

it checks if the alert is showing, and if it's showing it will tap it



回答4:

On xcode 9.1, alerts are only being handled if the test device has iOS 11. Doesn't work on older iOS versions e.g 10.3 etc. Reference: https://forums.developer.apple.com/thread/86989

To handle alerts use this:

//Use this before the alerts appear. I am doing it before app.launch()

let allowButtonPredicate = NSPredicate(format: "label == 'Always Allow' || label == 'Allow'")
//1st alert
_ = addUIInterruptionMonitor(withDescription: "Allow to access your location?") { (alert) -> Bool in
    let alwaysAllowButton = alert.buttons.matching(allowButtonPredicate).element.firstMatch
    if alwaysAllowButton.exists {
        alwaysAllowButton.tap()
        return true
    }
    return false
}
//Copy paste if there are more than one alerts to handle in the app


回答5:

I got it to work with this on Xcode 9.4.1, the trick was to wait for the popup to appear.

// wait for location service popup to appear
    let springboard = XCUIApplication(bundleIdentifier: "com.apple.springboard")
    let allowBtn = springboard.buttons["Allow"]
    expectation(for: NSPredicate(format: "exists == true"), evaluatedWith: allowBtn, handler: nil)
    waitForExpectations(timeout: 10, handler: nil)

    //allow location service
    if allowBtn.exists {
      allowBtn.tap()
    }


回答6:

To tap allow on location alert you can call element.tap() where element is any element on your screen. So after calling tap, accessibility will tap Allow on alert and than tap on your element



回答7:

This works for all languages:

        let springboard = XCUIApplication(bundleIdentifier: "com.apple.springboard")
        let allowBtn = springboard.buttons.element(boundBy: 2)
        if allowBtn.exists {
            allowBtn.tap()
        }