我如何替换在linux标签空格在一个给定的文本文件?
Answer 1:
使用unexpand(1)程序
UNEXPAND(1) User Commands UNEXPAND(1)
NAME
unexpand - convert spaces to tabs
SYNOPSIS
unexpand [OPTION]... [FILE]...
DESCRIPTION
Convert blanks in each FILE to tabs, writing to standard output. With
no FILE, or when FILE is -, read standard input.
Mandatory arguments to long options are mandatory for short options
too.
-a, --all
convert all blanks, instead of just initial blanks
--first-only
convert only leading sequences of blanks (overrides -a)
-t, --tabs=N
have tabs N characters apart instead of 8 (enables -a)
-t, --tabs=LIST
use comma separated LIST of tab positions (enables -a)
--help display this help and exit
--version
output version information and exit
. . .
STANDARDS
The expand and unexpand utilities conform to IEEE Std 1003.1-2001
(``POSIX.1'').
Answer 2:
我想你可以使用awk尝试
awk -v OFS="\t" '$1=$1' file1
或SED如果你preffer
sed 's/[:blank:]+/,/g' thefile.txt > the_modified_copy.txt
甚至TR
tr -s '\t' < thefile.txt | tr '\t' ' ' > the_modified_copy.txt
或TR溶液的简化版本由Sam比斯比sugested
tr ' ' \\t < someFile > someFile
Answer 3:
更好tr命令:
tr [:blank:] \\t
这将清理发言权的输出, 解压缩-l,以便进一步处理使用grep,剪切等
例如,
unzip -l some-jars-and-textfiles.zip | tr [:blank:] \\t | cut -f 5 | grep jar
Answer 4:
使用Perl:
perl -p -i -e 's/ /\t/g' file.txt
Answer 5:
下载并运行下面的脚本软标签递归转化为硬标签的纯文本文件。
地方,从包含纯文本文件的文件夹内执行脚本。
#!/bin/bash
find . -type f -and -not -path './.git/*' -exec grep -Iq . {} \; -and -print | while read -r file; do {
echo "Converting... "$file"";
data=$(unexpand --first-only -t 4 "$file");
rm "$file";
echo "$data" > "$file";
}; done;
Answer 6:
为当前目录下将每个js文件为制表符(唯一前导空格被转换)实施例的命令:
find . -name "*.js" -exec bash -c 'unexpand -t 4 --first-only "$0" > /tmp/totabbuff && mv /tmp/totabbuff "$0"' {} \;
Answer 7:
您还可以使用astyle
。 我发现它非常有用,它有几种选择太:
Tab and Bracket Options:
If no indentation option is set, the default option of 4 spaces will be used. Equivalent to -s4 --indent=spaces=4. If no brackets option is set, the
brackets will not be changed.
--indent=spaces, --indent=spaces=#, -s, -s#
Indent using # spaces per indent. Between 1 to 20. Not specifying # will result in a default of 4 spaces per indent.
--indent=tab, --indent=tab=#, -t, -t#
Indent using tab characters, assuming that each tab is # spaces long. Between 1 and 20. Not specifying # will result in a default assumption of
4 spaces per tab.`
Answer 8:
这将取代连续的空格用一个空格(但不是标签)。
tr -cs '[:space:]'
文章来源: Replace whitespaces with tabs in linux