Simulate a specific CURL in PostMan

问题:

I a using Postman to test some Curl requests to an API server. The API developer gave us the curl command, but I can't send it with Postman. How to make such a request?

curl -X POST "https://api-server.com/API/index.php/member/signin" -d "{"description":"","phone":"","lastname":"","app_version":"2.6.2","firstname":"","password":"my_pass","city":"","apikey":"213","lang":"fr","platform":"1","email":"[e-mail]","pseudo":"example"}"

--0xKhTmLbOuNdArY
Content-Disposition: form-data; name="userfile"; filename="profil.jpg"
Content-Type: image/jpeg
Content-Transfer-Encoding: binary

<ffd8ffe0 00104a46 49460001 01010048 ... a00fffd9>

—0xKhTmLbOuNdArY—

回答1:

A simpler approach would be:

1. Open POSTMAN
2. Click on "import" tab on the upper left side.
3. Select the Raw Text option and paste your cURL command.
4. Hit import and you will have the command in your Postman builder!

Hope this helps!

回答2:

In addition to the answer
1. Open POSTMAN
2. Click on "import" tab on the upper left side.
3. Select the Raw Text option and paste your cURL command.
4. Hit import and you will have the command in your Postman builder!
5. If -u admin:admin are not imported, just go to the Authorization 
   tab, select Basic Auth -> enter the user name eg admin and password eg admin.
This will automatically generate Authorization header based on Base64 encoder

回答3:

1) Put https://api-server.com/API/index.php/member/signin in the url input box and choose POST from the dropdown

2) In Headers tab, enter:

Content-Type: image/jpeg

Content-Transfer-Encoding: binary

3) In Body tab, select the raw radio button and write:

{"description":"","phone":"","lastname":"","app_version":"2.6.2","firstname":"","password":"my_pass","city":"","apikey":"213","lang":"fr","platform":"1","email":"[e-mail]","pseudo":"example"}

select form-data radio button and write:

key = name Value = userfile Select Text key = filename Select File and upload your profil.jpg

回答4:

I tried the approach mentioned by Onkaar Singh,

1. Open POSTMAN
2. Click on "import" tab on the upper left side.
3. Select the Raw Text option and paste your cURL command.
4. Hit import and you will have the command in your Postman builder!

But the problem is it didn't work for the Apis which requires authorisation.

This was my curl request:

curl -v -H "Accept: application/json" -H "Content-type:
application/json" -X POST -d ' 
{"customer_id":"812122", "event":"add_to_cart", "email": "[e-mail]", }' 
-u 9f4d7f5445e7: https://api.myapp.com/api/event

After importing the body got imported correctly, the headers and the Url also got imported. Only the api key 9f4d7f5445e7 which is

-u 9f4d7f5445e7: https://api.myapp.com/api/v1/event 

in the curl request did not import.

The way I solved it is, -u is basically used for Authorization. So while using it in Postman, you have to take the API key (which is 9f4d7f5445e7 in this case) and do Base64 Encode. Once encoded it will return the value OWY0ZDdmNTQ0NWU3. Then add a new header, the key name would be Authorization and key value would be Basic OWY0ZDdmNTQ0NWU3. After making that changes, the request worked for me.

There are online Base64 Encoders available, the one I used is http://www.url-encode-decode.com/base64-encode-decode/

Hope it helps!!!