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How can I convert String to Double without losing precision in Java?
4 answers
i want to develop one calculation base application but getting one problem.
Tried as below
double add_num = 10.06
String data = edittext.getText().toString();
value assign to data is
// data = 1000.06
now i am converting string to double
double amount = Double.parseDouble(data);
// amount = 1000.0
double final_amount = amount + add_num;
// final_amount = 1010.0
getting final_amount is 1000.0 which is not correct because amount value is losing precision i want the correct answer which is 1000.06
please let me know correct way without using format() method
Well, first of all correct value is 1010.12
, not 1000.06
. And this code:
double add_num = 10.06;
String value = "1000.06";
double amount = Double.parseDouble(value);
double final_amount = amount + add_num;
System.out.println(final_amount);
prints 1010.1199999999999
, which is correct.
If you just want to print the number with the desired precision, use one of:
// Prints with two decimal places: "1010.12"
System.out.format("%.2f", final_amount);
System.out.println(String.format("%.2f", final_amount));
// Example, set TextView text with two decimal places:
edittext.setText(String.format("%.2f", final_amount));
By the way, in your code you have:
String data = edittext.getText().toString();
double amount = Double.parseDouble(value); // value?
Shouldn't it be?
double amount = Double.parseDouble(data);
String s="1000.06";
double d=Double.parseDouble(s);
System.out.println(d);
The above code give output: 1000.06
You should use String.ValueOf(double d);
For Example:-
Double to String
String value=String.valueOf(1000.06);
OR
String value=String.valueOf(add_num);
String to Double
Double value=Double.valueOf("1000.06");
OR
Double value=Double.valueOf(add_num);