python list comprehensions; compressing a list of

问题:

guys. I'm trying to find the most elegant solution to a problem and wondered if python has anything built-in for what I'm trying to do.

What I'm doing is this. I have a list, A, and I have a function f which takes an item and returns a list. I can use a list comprehension to convert everything in A like so;

[f(a) for a in A]

But this return a list of lists;

[a1,a2,a3] => [[b11,b12],[b21,b22],[b31,b32]]

What I really want is to get the flattened list;

[b11,b12,b21,b22,b31,b32]

Now, other languages have it; it's traditionally called flatmap in functional programming languages, and .Net calls it SelectMany. Does python have anything similar? Is there a neat way to map a function over a list and flatten the result?

The actual problem I'm trying to solve is this; starting with a list of directories, find all the subdirectories. so;

import os
dirs = ["c:\\usr", "c:\\temp"]
subs = [os.listdir(d) for d in dirs]
print subs

currentliy gives me a list-of-lists, but I really want a list.

回答1:

You can have nested iterations in a single list comprehension:

[filename for path in dirs for filename in os.listdir(path)]

回答2:

>>> listOfLists = [[1, 2],[3, 4, 5], [6]]
>>> reduce(list.__add__, listOfLists)
[1, 2, 3, 4, 5, 6]

I'm guessing the itertools solution is more efficient than this, but this feel very pythonic and avoids having to import a library just for the sake of a single list operation.

回答3:

You can find a good answer in itertools' recipes:

def flatten(listOfLists):
    return list(chain.from_iterable(listOfLists))

(Note: requires Python 2.6+)

回答4:

The question proposed flatmap. Some implementations are proposed but they may unnecessary creating intermediate lists. Here is one implementation that's base on iterators.

def flatmap(func, *iterable):
    return itertools.chain.from_iterable(map(func, *iterable))

In [148]: list(flatmap(os.listdir, ['c:/mfg','c:/Intel']))
Out[148]: ['SPEC.pdf', 'W7ADD64EN006.cdr', 'W7ADD64EN006.pdf', 'ExtremeGraphics', 'Logs']

In Python 2.x, use itertools.map in place of map.

回答5:

You could just do the straightforward:

subs = []
for d in dirs:
    subs.extend(os.listdir(d))

回答6:

You can concatenate lists using the normal addition operator:

>>> [1, 2] + [3, 4]
[1, 2, 3, 4]

The built-in function sum will add the numbers in a sequence and can optionally start from a specific value:

>>> sum(xrange(10), 100)
145

Combine the above to flatten a list of lists:

>>> sum([[1, 2], [3, 4]], [])
[1, 2, 3, 4]

You can now define your flatmap:

>>> def flatmap(f, seq):
...   return sum([f(s) for s in seq], [])
... 
>>> flatmap(range, [1,2,3])
[0, 0, 1, 0, 1, 2]

Edit: I just saw the critique in the comments for another answer and I guess it is correct that Python will needlessly build and garbage collect lots of smaller lists with this solution. So the best thing that can be said about it is that it is very simple and concise if you're used to functional programming :-)

回答7:

import itertools
x=[['b11','b12'],['b21','b22'],['b31']]
y=list(itertools.chain(*x))
print y

itertools will work from python2.3 and greater

回答8:

subs = []
map(subs.extend, (os.listdir(d) for d in dirs))

(but Ants's answer is better; +1 for him)

回答9:

You could try itertools.chain(), like this:

import itertools
import os
dirs = ["c:\\usr", "c:\\temp"]
subs = list(itertools.chain(*[os.listdir(d) for d in dirs]))
print subs

itertools.chain() returns an iterator, hence the passing to list().

回答10:

Google brought me next solution:

def flatten(l):
   if isinstance(l,list):
      return sum(map(flatten,l))
   else:
      return l

回答11:

def flat_list(arr):
    send_back = []
    for i in arr:
        if type(i) == list:
            send_back += flat_list(i)
        else:
            send_back.append(i)
    return send_back

回答12:

You can use pyxtension:

from pyxtension.streams import stream
stream([ [1,2,3], [4,5], [], [6] ]).flatMap() == range(7)

回答13:

If listA=[list1,list2,list3]
flattened_list=reduce(lambda x,y:x+y,listA)

This will do.