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PHP get difference of two arrays of objects
3 answers
I have 2 object arrays: Array A and Array B. how can I check if object from Array B exists in Array A. and if exists remove it from Array A.
Example:
Array A:
[
{"id": 1, "name": "item1"},
{"id": 2, "name": "item2"},
{"id": 3, "name": "item3"},
{"id": 4, "name": "item4"}
]
Array B
[
{"id": 1, "name": "item1"},
{"id": 3, "name": "item3"}
]
After removing Array A should look like:
[
{"id": 2, "name": "item2"},
{"id": 4, "name": "item4"}
]
You can use array_udiff, and you can refer to these post for array compare post1 and post2. live demo
print_r(array_udiff($A, $B, function($a, $b){return $a['id'] == $b['id'] && $a['name'] == $b['name'] ? 0 : -1;}));
Here we are using array_map
which first convert object
's to string using json_encode
which will convert array to json string
then we are finding array_diff
for both the array's.
Try this code snippet here
<?php
ini_set('display_errors', 1);
$array1=
[
(object) ["id"=> 1, "name"=> "item1"],
(object) ["id"=> 2, "name"=> "item2"],
(object) ["id"=> 3, "name"=> "item3"],
(object) ["id"=> 4, "name"=> "item4"]
];
$array1=array_map(function($value){return json_encode($value);}, $array1);
$array2=
[
(object) ["id"=> 1, "name"=> "item1"],
(object) ["id"=> 3, "name"=> "item3"]
];
$array2=array_map(function($value){return json_encode($value);}, $array2);
$result=array_map(function($value){return json_decode($value);}, array_diff($array1, $array2));
print_r($result);
array_filter
might help.
$a = [
["id"=> 1, "name"=> "item1"],
["id"=> 2, "name"=> "item2"],
["id"=> 3, "name"=> "item3"],
["id"=> 4, "name"=> "item4"]
];
print_r(array_filter($a, function($e) {
return !in_array($e, [["id"=> 1, "name"=> "item1"],["id"=> 3, "name"=> "item3"]]);
}));
/* =>
Array
(
[1] => Array
(
[id] => 2
[name] => item2
)
[3] => Array
(
[id] => 4
[name] => item4
)
)
*/
http://php.net/manual/en/function.array-filter.php
http://php.net/manual/ru/function.in-array.php