Best way to get InnerXml of an XElement?

2019-01-02 17:58发布

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浪荡孟婆

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可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试):

问题:

What's the best way to get the contents of the mixed body element in the code below? The element might contain either XHTML or text, but I just want its contents in string form. The XmlElement type has the InnerXml property which is exactly what I'm after.

The code as written almost does what I want, but includes the surrounding <body>...</body> element, which I don't want.

XDocument doc = XDocument.Load(new StreamReader(s));
var templates = from t in doc.Descendants("template")
                where t.Attribute("name").Value == templateName
                select new
                {
                   Subject = t.Element("subject").Value,
                   Body = t.Element("body").ToString()
                };

回答1:

I wanted to see which of these suggested solutions performed best, so I ran some comparative tests. Out of interest, I also compared the LINQ methods to the plain old System.Xml method suggested by Greg. The variation was interesting and not what I expected, with the slowest methods being more than 3 times slower than the fastest.

The results ordered by fastest to slowest:

CreateReader - Instance Hunter (0.113 seconds)
Plain old System.Xml - Greg Hurlman (0.134 seconds)
Aggregate with string concatenation - Mike Powell (0.324 seconds)
StringBuilder - Vin (0.333 seconds)
String.Join on array - Terry (0.360 seconds)
String.Concat on array - Marcin Kosieradzki (0.364)

Method

I used a single XML document with 20 identical nodes (called 'hint'):

<hint>
  <strong>Thinking of using a fake address?</strong>
  <br />
  Please don't. If we can't verify your address we might just
  have to reject your application.
</hint>

The numbers shown as seconds above are the result of extracting the "inner XML" of the 20 nodes, 1000 times in a row, and taking the average (mean) of 5 runs. I didn't include the time it took to load and parse the XML into an XmlDocument (for the System.Xml method) or XDocument (for all the others).

The LINQ algorithms I used were: (C# - all take an XElement "parent" and return the inner XML string)

CreateReader:

var reader = parent.CreateReader();
reader.MoveToContent();

return reader.ReadInnerXml();

Aggregate with string concatenation:

return parent.Nodes().Aggregate("", (b, node) => b += node.ToString());

StringBuilder:

StringBuilder sb = new StringBuilder();

foreach(var node in parent.Nodes()) {
    sb.Append(node.ToString());
}

return sb.ToString();

String.Join on array:

return String.Join("", parent.Nodes().Select(x => x.ToString()).ToArray());

String.Concat on array:

return String.Concat(parent.Nodes().Select(x => x.ToString()).ToArray());

I haven't shown the "Plain old System.Xml" algorithm here as it's just calling .InnerXml on nodes.

Conclusion

If performance is important (e.g. lots of XML, parsed frequently), I'd use Daniel's CreateReader method every time. If you're just doing a few queries, you might want to use Mike's more concise Aggregate method.

If you're using XML on large elements with lots of nodes (maybe 100's), you'd probably start to see the benefit of using StringBuilder over the Aggregate method, but not over CreateReader. I don't think the Join and Concat methods would ever be more efficient in these conditions because of the penalty of converting a large list to a large array (even obvious here with smaller lists).

回答2:

I think this is a much better method (in VB, shouldn't be hard to translate):

Given an XElement x:

Dim xReader = x.CreateReader
xReader.MoveToContent
xReader.ReadInnerXml

回答3:

How about using this "extension" method on XElement? worked for me !

public static string InnerXml(this XElement element)
{
    StringBuilder innerXml = new StringBuilder();

    foreach (XNode node in element.Nodes())
    {
        // append node's xml string to innerXml
        innerXml.Append(node.ToString());
    }

    return innerXml.ToString();
}

OR use a little bit of Linq

public static string InnerXml(this XElement element)
{
    StringBuilder innerXml = new StringBuilder();
    doc.Nodes().ToList().ForEach( node => innerXml.Append(node.ToString()));

    return innerXml.ToString();
}

Note: The code above has to use element.Nodes() as opposed to element.Elements(). Very important thing to remember the difference between the two. element.Nodes() gives you everything like XText, XAttribute etc, but XElement only an Element.

回答4:

With all due credit to those who discovered and proved the best approach (thanks!), here it is wrapped up in an extension method:

public static string InnerXml(this XNode node) {
    using (var reader = node.CreateReader()) {
        reader.MoveToContent();
        return reader.ReadInnerXml();
    }
}

回答5:

Keep it simple and efficient:

String.Concat(node.Nodes().Select(x => x.ToString()).ToArray())

Aggregate is memory and performance inefficient when concatenating strings
Using Join("", sth) is using two times bigger string array than Concat... And looks quite strange in code.
Using += looks very odd, but apparently is not much worse than using '+' - probably would be optimized to the same code, becase assignment result is unused and might be safely removed by compiler.
StringBuilder is so imperative - and everybody knows that unnecessary "state" sucks.

回答6:

I ended up using this:

Body = t.Element("body").Nodes().Aggregate("", (b, node) => b += node.ToString());

回答7:

Personally, I ended up writing an InnerXml extension method using the Aggregate method:

public static string InnerXml(this XElement thiz)
{
   return thiz.Nodes().Aggregate( string.Empty, ( element, node ) => element += node.ToString() );
}

My client code is then just as terse as it would be with the old System.Xml namespace:

var innerXml = myXElement.InnerXml();

回答8:

@Greg: It appears you've edited your answer to be a completely different answer. To which my answer is yes, I could do this using System.Xml but was hoping to get my feet wet with LINQ to XML.

I'll leave my original reply below in case anyone else wonders why I can't just use the XElement's .Value property to get what I need:

@Greg: The Value property concatenates all the text contents of any child nodes. So if the body element contains only text it works, but if it contains XHTML I get all the text concatenated together but none of the tags.

回答9:

// using Regex might be faster to simply trim the begin and end element tag

var content = element.ToString();
var matchBegin = Regex.Match(content, @"<.+?>");
content = content.Substring(matchBegin.Index + matchBegin.Length);          
var matchEnd = Regex.Match(content, @"</.+?>", RegexOptions.RightToLeft);
content = content.Substring(0, matchEnd.Index);

回答10:

doc.ToString() or doc.ToString(SaveOptions) does the work. See http://msdn.microsoft.com/en-us/library/system.xml.linq.xelement.tostring(v=vs.110).aspx

回答11:

Is it possible to use the System.Xml namespace objects to get the job done here instead of using LINQ? As you already mentioned, XmlNode.InnerXml is exactly what you need.

回答12:

Wondering if (notice I got rid of the b+= and just have b+)

t.Element( "body" ).Nodes()
 .Aggregate( "", ( b, node ) => b + node.ToString() );

might be slightly less efficient than

string.Join( "", t.Element.Nodes()
                  .Select( n => n.ToString() ).ToArray() );

Not 100% sure...but glancing at Aggregate() and string.Join() in Reflector...I think I read it as Aggregate just appending a returning value, so essentially you get:

string = string + string

versus string.Join, it has some mention in there of FastStringAllocation or something, which makes me thing the folks at Microsoft might have put some extra performance boost in there. Of course my .ToArray() call my negate that, but I just wanted to offer up another suggestion.

回答13:

you know? the best thing to do is to back to CDATA :( im looking at solutions here but i think CDATA is by far the simplest and cheapest, not the most convenient to develop with tho

回答14:

var innerXmlAsText= XElement.Parse(xmlContent)
                    .Descendants()
                    .Where(n => n.Name.LocalName == "template")
                    .Elements()
                    .Single()
                    .ToString();

Will do the job for you

回答15:

public static string InnerXml(this XElement xElement)
{
    //remove start tag
    string innerXml = xElement.ToString().Trim().Replace(string.Format("<{0}>", xElement.Name), "");
    ////remove end tag
    innerXml = innerXml.Trim().Replace(string.Format("</{0}>", xElement.Name), "");
    return innerXml.Trim();
}

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