I'm writing a java servlet that calls a function in a jar. I have no control over the code in this jar. The function being called wants the filename of a configuration file as an argument.
I'd like to bundle this file with my war file. If I put it in the war somewhere, what filename can I pass the function in the jar?
Note that only a filename can be used with the jar's API. So ServletContext.getResourceAsStream() is not helpful.
Use ServletContext.getRealPath(). This returns the filesystem path for a given servlet context resource. You pass it the same argument as you would pass to ServletContext.getResourceAsStream()
Better yet, use Spring's Resource abstraction:
Resource resource = new ServletContextResource(servletContext, "/path/to/file");
File resourceFile = resource.getFile();
If it's in your .war file, you won't be able to access it as a file. Some servlet containers will explode a .war file into components, but I don't think you can rely on it.
Have you thought about extracting it (via getResourceAsStream()), writing it to a temp file/directory, and then referencing that ?
