How to use clone() to make parent process and chil

问题:

I'm new to linux. I want to make child process and parent process at the same time. But I have failed. Here is my code. Can anybody help me?

#define _GNU_SOURCE
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sched.h>
#include <signal.h>
#define FIBER_STACK 8192

void * stack;
int do_something(){
    int a = 0;
    while (a<10){
        printf("pid : %d, a = %d\n", getpid(), a++);
    }
    exit(1);
}
int main() {
    void * stack;
    stack = malloc(FIBER_STACK);
    if(!stack) {
        printf("The stack failed\n");
        exit(0);
    }

    int a = 0;
    if (c == 0)
        clone(&do_something, (char *)stack + FIBER_STACK, CLONE_VM|CLONE_VFORK, 0);
    while (a<10){
        printf("pid : %d, a = %d\n", getpid(), a++);
    }

    free(stack);
    exit(1);
}

I want them run in the same time, but the parent process wait until child process has finished.

回答1:

From clone

CLONE_VFORK (since Linux 2.2)
If CLONE_VFORK is set, the execution of the calling process is suspended until the child releases its virtual memory resources via a call to execve(2) or _exit(2) (as with vfork(2)).

If CLONE_VFORK is not set, then both the calling process and the child are schedulable after the call, and an application should not rely on execution occurring in any particular order.

This means with CLONE_VFORK, it is supposed to wait until the child finishes or does an exec.

Since you run a function in the child, you don't need exec. Just leave out the CLONE_VFORK

clone(&do_something, (char *)stack + FIBER_STACK, CLONE_VM, 0);

and both the parent and child will run concurrently.