I have this DataFrame on pandas:
import pandas as pd
df = pd.DataFrame({'CARGO': {53944: 'Driver',
57389: 'Driver',
60851: 'Driver',
64322: 'Driver',
67771: 'Driver'},
'DATE': {53944: '05/2015',
57389: '06/2015',
60851: '07/2015',
64322: '08/2015',
67771: '09/2015'},
'DESCRICAO': {53944: '\\Salario R$ 788,00\nGratificacao Adicional R$ 251,00\nGRATIFICAÇÃO R$ 512,00\nINSS R$ -104,00',
57389: '\\Salario R$ 788,00\nGratificacao Adicional R$ 251,00\nGRATIFICAÇÃO R$ 512,00\nINSS R$ -104,00',
60851: '\\Salario R$ 788,00\n1/3 de Ferias R$ 516,95\nGratificacao Adicional R$ 251,00\nGRATIFICAÇÃO R$ 512,00\nINSS R$ -104,00',
64322: '\\Salario R$ 788,00\nGratificacao Adicional R$ 251,00\nGRATIFICAÇÃO R$ 512,00\nINSS R$ -104,00',
67771: '\\Salario R$ 788,00\nGratificacao Adicional R$ 225,90\nGRATIFICAÇÃO R$ 512,00\nINSS R$ -104,00'},
'NOME': {53944: 'John Smith',
57389: 'John Smith',
60851: 'John Smith',
64322: 'John Smith',
67771: 'John Smith'}})
It renders this output:
]
How can I set up pandas or Jupyter so it will:
1. display plaintext
2. accept line break ('\n')
EDIT 1:
I´d like it to be like this:
You can try these things out, replace the new line character with html line break tag <br>
and explicitly using .to_html()
and HTML
for the display, and also set the max_colwidth
to be -1
so that the long line will not be truncated when converting to html
:
from IPython.core.display import HTML
pd.set_option('display.max_colwidth', -1)
df['DESCRICAO'] = df['DESCRICAO'].str.replace('\$', '\\$').str.replace('\n', '<br>')
HTML(df.to_html(escape=False))
The first part of the problem was solved.
On markdown, $ represents the start of a formula on mathjax. The solution is to inser a backslash before the symbol. Here is the snippet for pandas:
def fix_dollar_sign(x):
return re.sub('\$','\\$',x) # remember regex also uses dollar sign.
df['DESCRICAO'] = df['DESCRICAO'].apply(fix_dollar_sign)
.
I wasn´t able to make a new line inside the cell..
Expanding on Psidom's excellent answer, you can encapsulate it in a re-usable function. This way you won't alter your dataframe permanently either:
from IPython.core.display import HTML
def convert_newlines(s):
return s.replace('\n', '<br>') if isinstance(s, str) else s
def show_dataframe(df):
return HTML(df.applymap(convert_newlines).to_html(escape=False))
This opens up some interesting possibilities, like highliting some text on the dataframe html. Here is my try:
def highlight_text_on_descricao(df_rubrica = tab, texto='', cor='red'):
def marca_texto(x,text,color):
x, text, color, = str(x).upper(), str(text).upper(), str(color).lower()
marcador_primario = [m.start() for m in re.finditer(text , x)]
if marcador_primario == []:
return re.sub('\$','\\$',re.sub('\n','<br>',x))
contexto = ''
for item in marcador_primario:
marcador_inicio = x[:item].rfind('\n')
if marcador_inicio == -1:
marcador_inicio = 0
marcador_final = x.find("\n",item + 1)
if marcador_final == -1:
contexto += "<font color='" + color + "'><b> " + x[marcador_inicio:]
else:
contexto += "<font color='" + color + "'><b> " + x[marcador_inicio:marcador_final
] + '</font color></b>'
marcador_do_primeiro_vermelho = x[:marcador_primario[0]].rfind('\n')
if marcador_do_primeiro_vermelho == -1:
descricao = contexto + x[marcador_final:]
else:
descricao = x[:marcador_do_primeiro_vermelho] + contexto + x[marcador_final:]
return re.sub('\$','\\$',re.sub('\n','<br>',descricao))
df_temp = df_rubrica
df_temp = df_temp.rename(columns={'DESCRICAO':'DESCRICAO_LONG_TEXT_STRING____'})
df_temp['DESCRICAO_LONG_TEXT_STRING____'] = df_temp['DESCRICAO_LONG_TEXT_STRING____'].apply(marca_texto,args=(texto,cor,))
display(HTML(df_temp.to_html(escape=False)))
highlight_text_on_descricao(tab,'GRATIFICAÇÃO')
yelds:
(by the way, I got added some stuff on custom.css from Henry Hammond(https://github.com/HHammond/PrettyPandas), so that´s why headers and indexes are grey.