The ObjectId
used as the default key in mongodb documents has embedded timestamp (calling objectid.generation_time returns a datetime object). So it is possible to use this generation time instead of keeping a separate creation timestamp? How will you be able to sort by creation time or query for the last N items efficiently using this embedded timestamp?
问题:
回答1:
I suppose since MongoDB ObjectId contain a timestamp, you can sort by 'created date' if you will sort by objectId:
items.find.sort( [['_id', -1]] ) // get all items desc by created date.
And if you want last 30 created items you can use following query:
items.find.sort( [['_id', -1]] ).limit(30) // get last 30 createad items
I am actualy not sure,i just suppose that ordering by _id should work as described above. I'll create some tests later.
Update:
Yes it is so. If you order by _id you will automatically order by _id created date. I've done small test in c#, mb someone interest in it:
public class Item
{
[BsonId]
public ObjectId Id { get; set; }
public DateTime CreatedDate { get; set; }
public int Index { get; set; }
}
[TestMethod]
public void IdSortingTest()
{
var server = MongoServer.Create("mongodb://localhost:27020");
var database = server.GetDatabase("tesdb");
var collection = database.GetCollection("idSortTest");
collection.RemoveAll();
for (int i = 0; i <= 500; i++)
{
collection.Insert(new Item() {
Id = ObjectId.GenerateNewId(),
CreatedDate = DateTime.Now,
Index = i });
}
var cursor = collection.FindAllAs<Item>();
cursor.SetSortOrder(SortBy.Descending("_id"));
var itemsOrderedById = cursor.ToList();
var cursor2 = collection.FindAllAs<Item>();
cursor2.SetSortOrder(SortBy.Descending("CreatedDate"));
var itemsOrderedCreatedDate = cursor.ToList();
for (int i = 0; i <= 500; i++)
{
Assert.AreEqual(itemsOrderedById[i].Index, itemsOrderedCreatedDate[i].Index);
}
}
回答2:
Yes, you can use the generation_time of BSON ObjectId for the purposes you want. So,
db.collection.find().sort({ _id : -1 }).limit(10)
will return the last 10 created items. However, since the embedded timestamps have a one second precision, multiple items within any second are stored in the order of their creation.
回答3:
The code to convert a DateTime to its corresponding timestamp with the c# driver is as follows:
public static ObjectId ToObjectId(this DateTime dateTime)
{
var timestamp = (int)(dateTime - BsonConstants.UnixEpoch).TotalSeconds;
return new ObjectId(timestamp, 0, 0, 0);
}
More info here: http://www.danharman.net/2011/10/26/mongodb-ninjitsu-using-objectid-as-a-timestamp/
回答4:
See
http://www.mongodb.org/display/DOCS/Object+IDs#ObjectIDs-DocumentTimestamps
Likely doable however I would always prefer having a dedicated timestamp instead of relying on some such internals like timestamp somehow embedded in some object id.
回答5:
From: http://www.mongodb.org/display/DOCS/Object+IDs#ObjectIDs-DocumentTimestamps
"sorting on an _id field that stores ObjectId values is roughly equivalent to sorting by creation time, although this relationship is not strict with ObjectId values generated on multiple systems within a single second."
回答6:
To query projects created within 7 days, I use below snippet:
db.getCollection('projects').find({
$where: function() {
// last 7 days
return Date.now() - this._id.getTimestamp() < (7 * 24 * 60 * 60 * 1000)
}
}).sort({
'_id': -1
})
and if you want to get items with specified fields:
db.getCollection('projects').find({
$where: function() {
// last 7 days
return Date.now() - this._id.getTimestamp() < (7 * 24 * 60 * 60 * 1000)
}
}).sort({
'_id': -1
}).toArray().map(function(item) {
var res = {};
res['Project Name'] = item.config.label;
res['Author'] = item.author;
res['Created At'] = item._id.getTimestamp().toLocaleDateString();
res['Last Modified Date'] = item.config.lastModifDate.toLocaleString();
return res;
});
it will return something like this:
[{
"Project Name": "Newsletter",
"Author": "larry.chen",
"Created At": "Thursday, January 19, 2017",
"Last Modified Date": "Thursday, January 19, 2017 17:05:40"
}...]
PS: the software I use to connect to MongoDB is Robo 3T
Hope this will help you.