MVC Return Partial View as JSON

问题:

Is there a way to return an HTML string from rendering a partial as part of a JSON response from MVC?

    public ActionResult ReturnSpecialJsonIfInvalid(AwesomenessModel model)
    {
        if (ModelState.IsValid)
        {
            if(Request.IsAjaxRequest()
                return PartialView("NotEvil", model);
            return View(model)
        }
        if(Request.IsAjaxRequest())
        {
            return Json(new { error=true, message = PartialView("Evil",model)});
        }
        return View(model);
    }

回答1:

You can extract the html string from the PartialViewResult object, similar to the answer to this thread:

Render a view as a string

PartialViewResult and ViewResult both derive from ViewResultBase, so the same method should work on both.

Using the code from the thread above, you would be able to use:

public ActionResult ReturnSpecialJsonIfInvalid(AwesomenessModel model)
{
    if (ModelState.IsValid)
    {
        if(Request.IsAjaxRequest())
            return PartialView("NotEvil", model);
        return View(model)
    }
    if(Request.IsAjaxRequest())
    {
        return Json(new { error = true, message = RenderViewToString(PartialView("Evil", model))});
    }
    return View(model);
}

回答2:

Instead of RenderViewToString I prefer a approach like

return Json(new { Url = Url.Action("Evil", model) });

then you can catch the result in your javascript and do something like

success: function(data) {
    $.post(data.Url, function(partial) { 
        $('#IdOfDivToUpdate').html(partial);
    });
}

回答3:

Url.Action("Evil", model)

will generate a get query string but your ajax method is post and it will throw error status of 500(Internal Server Error). – Fereydoon Barikzehy Feb 14 at 9:51

Just Add "JsonRequestBehavior.AllowGet" on your Json object.