How do I get the last character of a string?

2019-01-12 23:32发布

问题:

How do I get the last character of a string?

public class Main
{
    public static void main(String[] args) 
    {
        String s = "test string";
        //char lastChar = ???
    }   
}

回答1:

The code:

public class Test {
    public static void main(String args[]) {
        String string = args[0];
        System.out.println("last character: " +
                           string.substring(string.length() - 1)); 
    }
}

The output:

last character: f


回答2:

Here is a method using String.charAt():

String str = "India";
System.out.println("last char = " + str.charAt(str.length() - 1));

The resulting output is last char = a.



回答3:

The other answers contain a lot of needless text and code. Here are two ways to get the last character of a String:

char

char lastChar = myString.charAt(myString.length() - 1);

String

String lastChar = myString.substring(myString.length() - 1);


回答4:

The other answers are very complete, and you should definitely use them if you're trying to find the last character of a string. But if you're just trying to use a conditional (e.g. is the last character 'g'), you could also do the following:

if (str.endsWith("g")) {

or, strings

if (str.endsWith("bar")) {


回答5:

Try this:

if (s.charAt(0) == s.charAt(s.length() - 1))


回答6:

Simple solution is:

public String frontBack(String str) {
  if (str == null || str.length() == 0) {
    return str;
  }
  char[] cs = str.toCharArray();
  char first = cs[0];
  cs[0] = cs[cs.length -1];
  cs[cs.length -1] = first;
  return new String(cs);
}

Using a character array (watch out for the nasty empty String or null String argument!)

Another solution uses StringBuilder (which is usually used to do String manupilation since String itself is immutable.

public String frontBack(String str) {
  if (str == null || str.length() == 0) {
    return str;
  }
  StringBuilder sb = new StringBuilder(str);  
  char first = sb.charAt(0);
  sb.setCharAt(0, sb.charAt(sb.length()-1));
  sb.setCharAt(sb.length()-1, first);
  return sb.toString();
}

Yet another approach (more for instruction than actual use) is this one:

public String frontBack(String str) {
  if (str == null || str.length() < 2) {
    return str;
  }
  StringBuilder sb = new StringBuilder(str);
  String sub = sb.substring(1, sb.length() -1);
  return sb.reverse().replace(1, sb.length() -1, sub).toString();
}

Here the complete string is reversed and then the part that should not be reversed is replaced with the substring. ;)



回答7:

public String lastChars(String a) {
if(a.length()>=1{
String str1 =a.substring(b.length()-1);
}
return str1;
}


回答8:

public char LastChar(String a){
    return a.charAt(a.length() - 1);
}


回答9:

String aString = "This will return the letter t";
System.out.println(aString.charAt(aString.length() - 1));

Output should be:

t

Happy coding!



回答10:

 public char lastChar(String s) {
     if (s == "" || s == null)
        return ' ';
    char lc = s.charAt(s.length() - 1);
    return lc;
}