dateTime to Epoch and vice versa xslt

问题:

I have been trying to convert a given dateTime to epoch time and also a given epoch time to dateTime. I am quite new to xslt and have been struggling with this quite for some time, it is not giving me back any results. Here is my xslt so far

    <xsl:stylesheet version="1.0"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                xmlns:ns0="http://www.NoPreAuth.org"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                exclude-result-prefixes="xsi xsl ns0 xsd">
<xsl:template match="/">
<xsl:variable name="date1">
        <xsl:value-of select="/ns0:NoAuthInput/ns0:StartDate"/>
</xsl:variable>
<xsl:variable name="date2">
        <xsl:value-of select="/ns0:NoAuthInput/ns0:EndDate"/>
</xsl:variable>
<ns0:NoPreAuthInput>
<ns0:Product>
        <xsl:value-of select="/ns0:NoAuthInput/ns0:Product"/>
</ns0:Product>
<!-- datTime to epoch -->
<ns0:END_T> 
  <xsl:value-of select= "(('$date1')  - xsd:dateTime('1970-01-01T00:00:00') )  div  xsd:dayTimeDuration('PT1S') "/>
</ns0:END_T>
<!-- epoch To datTime -->
<ns0:Closed_T> 
  <xsl:value-of select= "(('$date2')  + xsd:dateTime('1970-01-01T00:00:00') )  *  xsd:dayTimeDuration('PT1S') "/>
</ns0:Closed_T>
</ns0:NoPreAuthInput>
</xsl:template>
</xsl:stylesheet>

and the xml which I am trying to convert is:

<?xml version="1.0" encoding="UTF-8" ?>
<NoAuthInput xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.NoAuth.org 

 xmlns="http://www.NoAuth.org">
   <Product>ABC</Product>
   <StartDate>2015-10-05T15:52:40.782</StartDate>
   <EndDate>1444150760</EndDate>
</NoAuthInput> 

any help on this much appreciated. Thanks

回答1:

To convert Unix time to ISO 8601 date-time:

<xsl:value-of select="xs:dateTime('1970-01-01T00:00:00') + xs:dayTimeDuration(concat('PT', UnixTime, 'S'))"/>

To convert ISO 8601 date-time to Unix time;

<xsl:value-of select="floor((xs:dateTime(ISODateTime) - xs:dateTime('1970-01-01T00:00:00')) div xs:dayTimeDuration('PT1S')) "/>

Requires XSLT 2.0.

Working demo: http://xsltransform.net/94rmq5L

回答2:

If you are trying to do this in XSLT 1.0 on MSXML (I know the original asker is not):

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:ms="urn:schemas-microsoft-com:xslt" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:userCSharp="http://stackoverflow.com/xsltexample">
  <xsl:output method="xml" omit-xml-declaration="yes" indent="yes" />
  <xsl:template match="/">
    <xsl:value-of select="userCSharp:DateToEpoch('1970-01-02')" />
  </xsl:template>
  <msxsl:script language="CSharp" implements-prefix="userCSharp"><![CDATA[
     public string DateToEpoch(string s)
     {
         DateTime dt = DateTime.Parse(s);  
         DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);

         return (dt - epoch).TotalSeconds.ToString();
     }
   ]]></msxsl:script>
</xsl:stylesheet>

Replace the '1970-01-02' with whatever text node you want and this should work, as long as that node was a valid date time. If not, it's easy enough to write up another simple method to do that using DateTime.Parse/TryParse. The output of this template (against any valid XML) would be 86400. Note that it's best to define methods in a CDATA node to avoid needing to escape quotes or angle brackets (this code doesn't happen to use any but might be extended to for some reason).