I would like to have the same Makefile for building on Linux and on Windows. I use the default GNU make on Linux and the mingw32-make (also GNU make) on Windows.
I want the Makefile to detect whether it operates on Windows or Linux.
For example make clean
command on Windows looks like:
clean:
del $(DESTDIR_TARGET)
But on Linux:
clean:
rm $(DESTDIR_TARGET)
Also I would like to use different directory separator on Windows (\
) and Linux (/
).
It is possible to detect Windows operating system in Makefile?
PS: I do not want to emulate Linux on Windows (cygwin etc.)
There is similiar question: OS detecting makefile, but I didn't find the answer here.
I solved this by looking for an env variable that will only be set on windows.
ifdef OS
RM = del /Q
FixPath = $(subst /,\,$1)
else
ifeq ($(shell uname), Linux)
RM = rm -f
FixPath = $1
endif
endif
clean:
$(RM) $(call FixPath,objs/*)
Because %OS% is the type of windows, it should be set on all Windows computers but not on Linux.
The blocks then setups up variables for the different programs as well as a function for converting the forward slashes into backslashes.
You to have to use $(call FixPath,path) when you call an outside command (internal commands work fine). You could also use something like:
/ := /
and then
objs$(/)*
if you like that format better.
The SystemRoot trick didn't work for me on Windows XP but this did:
ifeq ($(OS),Windows_NT)
#Windows stuff
...
else
#Linux stuff
....
endif
You should probably use the $(RM) variable to remove some files.
I would like to have the same Makefile for building on Linux and on Windows.
Maybe you will like CMake
Checking WINDIR or COMSPEC is case-sensitive. Instead, I came up
with the following solution, hope that helps someone someday:
# detect if running under unix by finding 'rm' in $PATH :
ifeq ($(wildcard $(addsuffix /rm,$(subst :, ,$(PATH)))),)
WINMODE=1
else
WINMODE=0
endif
ifeq ($(WINMODE),1)
# native windows setup :
UNLINK = del $(subst /,\,$(1))
CAT = type $(subst /,\,$(1))
else
# cross-compile setup :
UNLINK = $(RM) $(1)
CAT = cat $(1)
endif