JsonConvert.DeserializeObject special characters U

2019-07-08 05:16发布

问题:

For some reason, when I have a special character in my knockout model and convert it to a json object, the string ends where the special character is supposed to be and I get an error when deserializing it:

$.ajax({
    url: "/Admin/Forms/Convert",
    type: "post",
        //contentType: "application/json",
        dataType: "text",
        data: "modelData=" + ko.toJSON(theModel),
        success: function (data) {

            // window.open("/Admin/Forms/DisplayClient");
            var win = getFullWindow('/Admin/Forms/DisplayClient');
            win.open();
        },
        error: function (xhr, status, msg) { alert(msg); }
    });

When I get to this method:

public void Convert(string modelData)
{
    Form form = JsonConvert.DeserializeObject<Form>(modelData);
}

I get an error:

Unterminated string. Expected delimiter: ". Path 'Name', line 1, position 178.

回答1:

If a JSON string contains special characters like double quotes ", backslashes \ or slashes /, they need to be escaped with backslashes \. There is no JSON parser that will be able to deal with a JSON string that isn't properly formatted in the first place.

So you need to make sure that your theModel is formatted appropriately and according to JSON.org standards.



回答2:

I have got the same error a few times. I have updated my web.config with greater max lengths to ensure no truncating.

<httpRuntime maxQueryStringLength="2097151" maxUrlLength="2097151" />

<security>
  <requestFiltering>
    <requestLimits maxQueryString="2097151" maxUrl="2097151" />
  </requestFiltering>
</security>

The encodeURIComponent() function encodes a URI component.

This function encodes special characters. In addition, it encodes the following characters: , / ? : @ & = + $ #

This has now been added to my ajax requests:

$.ajax("URL", {
    type: "POST",
    cache: false,
    data: { a: encodeURIComponent(jsonData), b: userID }
})


回答3:

I found an answer to my own question: escape(ko.toJSON(theModel)) All I need is the escape function and it works great.