我想几列的2代不同表的总和(这些表共享相同的结构)。
如果我只考虑一个表,我会写这样的查询:
SELECT MONTH_REF, SUM(amount1), SUM(amount2)
FROM T_FOO
WHERE seller = XXX
GROUP BY MONTH_REF;
不过,我想也有从表T_BAR数据的工作,然后有一个select
返回下面的列的查询:
- MONTH_REF
- SUM(T_FOO.amount1)+ SUM(T_BAR.amount1)
- SUM(T_FOO.amount2)+ SUM(T_BAR.amount2)
一切由价值分组MONTH_REF
。
请注意,对于一个给定的记录MONTH_REF
可以在一个表中,但不会在其他表中找到。 在这种情况下,我想获得的总和T_FOO.amount1 + 0
(或0 + T_BAR.amount1
)。
我怎么能写我的SQL查询来获取这些信息?
有关信息,我的数据库是Oracle 10g中。
您可以联合小组通过(这是甲骨文的方式)之前,你的表:
SELECT t.month_ref, SUM(t.amount1), SUM(t.amount2)
FROM (SELECT month_ref, amount1, amount2
FROM T_FOO
WHERE seller = XXX
UNION ALL
SELECT month_ref, amount1, amount2
FROM T_BAR
WHERE seller = XXX
) t
GROUP BY t.month_ref
您也可以联合与后来卖家领域和过滤通过它(你需要更先进的逻辑的情况下)的表:
SELECT t.month_ref, SUM(t.amount1), SUM(t.amount2)
FROM (SELECT month_ref, amount1, amount2, seller
FROM T_FOO
UNION ALL
SELECT month_ref, amount1, amount2, seller
FROM T_BAR) t
where t.seller = XXX
GROUP BY t.month_ref
您是否使用工会试过吗?
SELECT MONTH_REF, SUM(amount1), SUM(amount2)
FROM (
SELECT MONTH_REF, SUM(amount1) AS amount1, SUM(amount2) as amount2
FROM T_FOO
WHERE seller = XXX
GROUP BY MONTH_REF
UNION ALL SELECT MONTH_REF, SUM(amount1), SUM(amount2)
FROM T_BAR
WHERE seller = XXX
GROUP BY MONTH_REF
) tmp
GROUP BY MONTH_REF
另外,外部联接也应努力:
SELECT month_ref,
SUM(t_foo.amount1) + SUM(t_bar.amount1),
SUM(t_foo.amount2)+SUM(t_bar.amount2)
FROM t_foo FULL OUTER JOIN t_bar
ON t_foo.month_ref = t_bar.month_ref
GROUP BY month_ref
我终于用这个工作利芬的答案。
下面是正确的代码( amount1 = ...
不工作我的环境,有太多;
查询):
SELECT MONTH_REF, SUM(sumAmount1), SUM(sumAmount2)
FROM (
SELECT MONTH_REF, SUM(amount1) as sumAmount1, SUM(amount2) as sumAmount1
FROM T_FOO
WHERE seller = XXX
GROUP BY MONTH_REF
UNION ALL SELECT MONTH_REF, SUM(amount1), SUM(amount2)
FROM T_BAR
WHERE seller = XXX
GROUP BY MONTH_REF
) tmp
GROUP BY MONTH_REF
SELECT (SELECT SUM(amount) from debit) as debitamounts, (SELECT SUM(amount) from credit) as creditamounts