选择一个行与列上的MAX（）值(SELECT ONE Row with the MAX() valu

我每月通讯的一个非常简单的数据集：

id  | Name          | PublishDate   | IsActive
1   |  Newsletter 1 | 10/15/2012    |     1
2   |  Newsletter 2 | 11/06/2012    |     1  
3   |  Newsletter 3 | 12/15/2012    |     0
4   |  Newsletter 4 | 1/19/2012     |     0

等等。

该PublishDate是独一无二的。

结果（基于上面）：

id  | Name          | PublishDate   | IsActive
2   |  Newsletter 2 | 11/06/2012    |     1  

我要的是非常简单的。 我只是想在1个通讯是IsActive和PublishDate = MAX（PublishDate）。

Answer 1:

select top 1 * from newsletters where IsActive = 1 order by PublishDate desc

Answer 2:

您可以使用row_number()

select id, name, publishdate, isactive
from
(
  select id, name, publishdate, isactive,
    row_number() over(order by publishdate desc) rn
  from table1
  where isactive = 1
) src
where rn = 1

请参阅SQL拨弄演示

你甚至可以使用选择的子查询max()日期：

select t1.*
from table1 t1
inner join
(
  select max(publishdate) pubdate
  from table1
  where isactive = 1
) t2
  on t1.publishdate = t2.pubdate

请参阅SQL拨弄演示

Answer 3:

CREATE TABLE Tmax(Id INT,NAME VARCHAR(15),PublishedDate DATETIME,IsActive BIT)
INSERT INTO Tmax(Id,Name,PublishedDate,IsActive)
VALUES(1,'Newsletter 1','10/15/2012',1),(2,'Newsletter 2','11/06/2012',1),(3,'Newsletter 3','12/15/2012',0),(4,'Newsletter 4','1/19/2012',0)

SELECT * FROM Tmax

SELECT t.Id
        ,t.NAME
        ,t.PublishedDate
        ,t.IsActive
FROM Tmax AS t
    WHERE PublishedDate=
    (
        SELECT TOP 1 MAX(PublishedDate)
        FROM Tmax
        WHERE IsActive=1
    )

文章来源: SELECT ONE Row with the MAX() value on a column