有没有一种方法来刷新单个剑道网格行,而不刷新整个数据源或使用jQuery设置每个单元格的值?
Answer 1:
你如何定义你想要更新的行? 我会认为是你选择了行,被更新的列的名称是symbol
。
// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");
// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);
// update the column `symbol` and set its value to `HPQ`
data.set("symbol", "HPQ");
请记住,内容DataSource
是一个observable
对象,这意味着您可以使用更新set
和变更应神奇地反射grid
。
Answer 2:
data.set
实际上将刷新整个电网和发送databound
在某些情况下的事件。 这是非常缓慢和不必要的。 它也将崩溃任何扩展的详细信息模板是不理想的。
我会建议你使用这个功能,我写在剑道网更新一行。
// Updates a single row in a kendo grid without firing a databound event.
// This is needed since otherwise the entire grid will be redrawn.
function kendoFastRedrawRow(grid, row) {
var dataItem = grid.dataItem(row);
var rowChildren = $(row).children('td[role="gridcell"]');
for (var i = 0; i < grid.columns.length; i++) {
var column = grid.columns[i];
var template = column.template;
var cell = rowChildren.eq(i);
if (template !== undefined) {
var kendoTemplate = kendo.template(template);
// Render using template
cell.html(kendoTemplate(dataItem));
} else {
var fieldValue = dataItem[column.field];
var format = column.format;
var values = column.values;
if (values !== undefined && values != null) {
// use the text value mappings (for enums)
for (var j = 0; j < values.length; j++) {
var value = values[j];
if (value.value == fieldValue) {
cell.html(value.text);
break;
}
}
} else if (format !== undefined) {
// use the format
cell.html(kendo.format(format, fieldValue));
} else {
// Just dump the plain old value
cell.html(fieldValue);
}
}
}
}
例:
// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");
// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);
// Update any values that you want to
data.symbol = newValue;
data.symbol2 = newValue2;
...
// Redraw only the single row in question which needs updating
kendoFastRedrawRow(grid, select);
// Then if you want to call your own databound event to do any funky post processing:
myDataBoundEvent.apply(grid);
Answer 3:
我发现了一个方法来更新在网格中网格数据源,并显示无刷新全部并网发电。 例如你有一个选择的行,你想更改列“名称”值。
//the grid
var grid = $('#myGrid').data('kendoGrid');
// Access the row that is selected
var row = grid.select();
//gets the dataItem
var dataItem = grid.dataItem(row);
//sets the dataItem
dataItem.name = 'Joe';
//generate a new row html
var rowHtml = grid.rowTemplate(dataItem);
//replace your old row html with the updated one
row.replaceWith(rowHtml);
文章来源: Refresh a single Kendo grid row