问题1:
SELECT COUNT (A.EMPNO) AS [PRESENT]
FROM ERPDATA.NIITESS.DBO.ZEMP_MASXST_WEB_AL A INNER
JOIN PPA_EVENTWISEEMPLOYEEMASTER B ON
(CASE B.VC_BA WHEN '%' THEN LTRIM(RTRIM(A.PDIBUSHORT)) ELSE B.VC_BA END) = LTRIM(RTRIM(A.PDIBUSHORT))
AND (CASE B.VC_PA WHEN '%' THEN A.PA ELSE B.VC_PA END) = A.PA
WHERE A.STATUS = 3
AND A.EMPNO IN (SELECT VC_EMPCODE FROM ERPDATA.NIITESS.DBO.ADA_MXEASTER WHERE IN_ATTENDANCE_STATUS = 1 AND CH_ACTIVE = 'Y' AND VC_EMPCODE <> '')
GROUP BY B.IN_EVENTID
问题2:
SELECT COUNT (A.EMPNO) AS [TOTAL]
FROM ERPDATA.NIITESS.DBO.ZEMP_MASXST_WEB_AL A INNER
JOIN PPA_EVENTWISEEMPLOYEEMASTER B ON
(CASE B.VC_BA WHEN '%' THEN LTRIM(RTRIM(A.PDIBUSHORT)) ELSE B.VC_BA END) = LTRIM(RTRIM(A.PDIBUSHORT))
AND (CASE B.VC_PA WHEN '%' THEN A.PA ELSE B.VC_PA END) = A.PA
WHERE A.STATUS = 3
我想这两个结果为两列与列缺席合并=查询2 - 查询1至更快的处理速度。 我该怎么做? 示例:
我有两个结果:
// ---------------------------------------- QUERY:1
1
2
3
4
// -------------------------------------- QUERY:2
4
五
6
8
// ------------------------------------结果一样在两列
1 5
2 6
3 7
4 8