like the title says, how to get the element's x, y positions with respect to their location in the web page and their positioning schemes like absolute, relative etc.
问题:
回答1:
In a modern browser, getBoundingClientRect and getClientRects will give you rect objects describing your element. See https://developer.mozilla.org/en/DOM/element.getBoundingClientRect and https://developer.mozilla.org/en/DOM/element.getClientRects
If you have to work with IE8, then you'll have to do different things in different browsers to get correct answers (e.g. object-detect getBoundingClientRect and fall back on some other method if it's not present).
The jQuery offset()
calculation and the Quirksmode findPos
will give incorrect answers in any browser that does subpixel positioning (e.g. Firefox or IE9), because they will round the answer to an integer number of pixels. Depending on what you're doing, that may or may not be ok.
回答2:
With jQuery:
var $elt = $('select an element however'),
cssPosition = $elt.css('position'),
offset = $elt.offset(),
top = offset.top,
left = offset.left;
Without jQuery, use Quirksmode's findPos
function:
var elt = document.getElementBy...,
pos = findPos(elt),
top = pos[1],
left = pos[0];
Getting the computed CSS position
value without a library is another can of worms. It boils down to:
element.currentStyle
(IE)getComputedStyle(element)
(real browsers)
回答3:
Check out this
JS:
function findPos(obj) {
var curleft = curtop = 0;
if (obj.offsetParent) {
curleft = obj.offsetLeft
curtop = obj.offsetTop
while (obj = obj.offsetParent) {
curleft += obj.offsetLeft
curtop += obj.offsetTop
}
}
return [curleft,curtop];
}
HTML:
<div id="ser"> TEST</div>
RETURN CALL:
alert(findPos(document.getElementById('ser')));
I hope its help to you