I just want to get the files from the current dir and only output .mp4 .mp3 .exe files nothing else.
So I thought I could just do this:
ls | grep \.mp4$ | grep \.mp3$ | grep \.exe$
But no, as the first grep will output just mp4's therefor the other 2 grep's won't be used.
Any ideas? PS, Running this script on Slow Leopard.
Why not:
ls *.{mp3,exe,mp4}
I'm not sure where I learned it - but I've been using this.
Use regular expressions with find
:
find . -iregex '.*\.\(mp3\|mp4\|exe\)' -printf '%f\n'
If you're piping the filenames:
find . -iregex '.*\.\(mp3\|mp4\|exe\)' -printf '%f\0' | xargs -0 dosomething
This protects filenames that contain spaces or newlines.
OS X find
only supports alternation when the -E
(enhanced) option is used.
find -E . -regex '.*\.(mp3|mp4|exe)'
egrep
-- extended grep -- will help here
ls | egrep '\.mp4$|\.mp3$|\.exe$'
should do the job.
the easiest way is to just use ls
ls *.mp4 *.mp3 *.exe
Just in case: why don't you use find
?
find -iname '*.mp3' -o -iname '*.exe' -o -iname '*.mp4'
No need for grep. Shell wildcards will do the trick.
ls *.mp4 *.mp3 *.exe
If you have run
shopt -s nullglob
then unmatched globs will be removed altogether and not be left on the command line unexpanded.
If you want case-insensitive globbing (so *.mp3 will match foo.MP3):
shopt -s nocaseglob
In case you are still looking for an alternate solution:
ls | grep -i -e '\\.tcl$' -e '\\.exe$' -e '\\.mp4$'
Feel free to add more -e flags if needed.
For OSX users:
If you use ls *.{mp3,exe,mp4}
, it will throw an error if one of those extensions has no results.
Using ls *.(mp3|exe|mp4)
will return all files matching those extensions, even if one of the extensions had 0 results.
ls | grep "\.mp4$
\.mp3$
\.exe$"
ls -R | findstr ".mp3"
ls -R
=> lists subdirectories recursively
Here is one example that worked for me.
find <mainfolder path> -name '*myfiles.java' | xargs -n 1 basename