Converting a Curl command to run in a Zapier Webho

问题:

I'm trying to find a way to run this curl command in the Webhook Zap on Zapier, but I can't seem to figure it out. How would I enter this in the Webhook? Would it be better to run it as a Code Zap?

curl -X POST "https://api.zoom.us/v2/users?access_token=eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpc3MiOiJmY3FvTHlyRVRpR3VmWmw2dW1ZU2NBIiwiaWF0IjoxNTI4Njc0OTUxLCJleHAiOjE1Mjg2OTI5NTF9.fvDzS8-UtHyO_YUF5-eqLyuopAuoL48SRwKxcOV1YrE" -H "accept: application/json" -H "Content-Type: application/json" -d "{ \"action\": \"create\", \"user_info\": { \"email\": \"[e-mail]\", \"type\": 1, \"first_name\": \"Chris\", \"last_name\": \"G\", \"password\": \"Test54321\" }}"

回答1:

David here, from the Zapier Platform team. Luckily, this is an easy one. Since you're using nested data, you'll need to use Webhooks by Zapier's Custom Request. The setup is the following:

Body & URL:

Headers:

You can also do it through code, you'll have the same result.

Also, if that access_token is still live, make sure to revoke it now that it's been out in the public!