嗨,我能得到使用此代码事件
cur = null;
cr = getContentResolver();
// Construct the query with the desired date range.
Uri.Builder builder = Instances.CONTENT_URI.buildUpon();
ContentUris.appendId(builder, 0);
ContentUris.appendId(builder, endMillis);
// Submit the query
cur = cr.query(builder.build(),
INSTANCE_PROJECTION,
null,
null,
null);
但正如你看到的,我可以给定的持续时间内只得到事件,但我需要所有的事件(不包括没有重复事件的任何时间规范)这可能吗? 如何 ? 请帮我。
cur = cr.query(Uri.parse("content://com.android.calendar/events"),
INSTANCE_PROJECTION,
null,
null,
null);
它提供了错误java.lang.IllegalArgumentException异常:
试试这个代码...
public class Utility {
public static ArrayList<String> nameOfEvent = new ArrayList<String>();
public static ArrayList<String> startDates = new ArrayList<String>();
public static ArrayList<String> endDates = new ArrayList<String>();
public static ArrayList<String> descriptions = new ArrayList<String>();
public static ArrayList<String> readCalendarEvent(Context context) {
Cursor cursor = context.getContentResolver()
.query(
Uri.parse("content://com.android.calendar/events"),
new String[] { "calendar_id", "title", "description",
"dtstart", "dtend", "eventLocation" }, null,
null, null);
cursor.moveToFirst();
// fetching calendars name
String CNames[] = new String[cursor.getCount()];
// fetching calendars id
nameOfEvent.clear();
startDates.clear();
endDates.clear();
descriptions.clear();
for (int i = 0; i < CNames.length; i++) {
nameOfEvent.add(cursor.getString(1));
startDates.add(getDate(Long.parseLong(cursor.getString(3))));
endDates.add(getDate(Long.parseLong(cursor.getString(4))));
descriptions.add(cursor.getString(2));
CNames[i] = cursor.getString(1);
cursor.moveToNext();
}
return nameOfEvent;
}
public static String getDate(long milliSeconds) {
SimpleDateFormat formatter = new SimpleDateFormat(
"dd/MM/yyyy hh:mm:ss a");
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(milliSeconds);
return formatter.format(calendar.getTime());
}
}
您还可以检查此
从日历中获取事件