我想获得的图像的大小蟒蛇,因为我用C ++做。
int w = src->width;
printf("%d", 'w');
我想获得的图像的大小蟒蛇,因为我用C ++做。
int w = src->width;
printf("%d", 'w');
使用功能GetSize
从模块cv
与你的形象作为参数。 它返回宽度,高度与2个元素的元组:
width, height = cv.GetSize(src)
使用opencv和numpy的是,因为这很容易:
import numpy as np
import cv2
img = cv2.imread('your_image.jpg',0)
height, width = img.shape[:2]
我用numpy.size()做相同的:
import numpy as np
import cv2
image = cv2.imread('image.jpg')
height = np.size(image, 0)
width = np.size(image, 1)
对我来说,最简单的方法是采取由image.shape返回的所有值:
height, width, channels = img.shape
如果你不想要的通道数(以确定是否该图像是BGR或灰度有用)刚落值:
height, width, _ = img.shape
这里是返回图像尺寸的方法:
from PIL import Image
import os
def get_image_dimensions(imagefile):
"""
Helper function that returns the image dimentions
:param: imagefile str (path to image)
:return dict (of the form: {width:<int>, height=<int>, size_bytes=<size_bytes>)
"""
# Inline import for PIL because it is not a common library
with Image.open(imagefile) as img:
# Calculate the width and hight of an image
width, height = img.size
# calculat ethe size in bytes
size_bytes = os.path.getsize(imagefile)
return dict(width=width, height=height, size_bytes=size_bytes)
我们可以使用frame = cv2.resize(frame, (width,height))
这里是一个简单的例子-
import cv2
import numpy as np
frame = cv2.imread("temp/i.jpg")
frame = cv2.resize(frame, (500,500))
cv2.imshow('frame', frame)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cv2.destroyAllWindows()