Is there a way in MySQL to do a single SQL statement that returns the selected rows along with the count of the result rows?
I can do this:
SELECT COUNT(*) FROM BigTable WHERE firstname LIKE 'a%';
Which gives me a single result row with the count (37,781). I can get the actual row data like this:
SELECT firstname FROM BigTable WHERE firstname LIKE 'a%';
which displays the actual 37,781 rows. But when I try to combine them, like this:
SELECT firstname, COUNT(*) FROM BigTable WHERE firstname LIKE 'a%';
I get a single row with the first row that matches the query, and the total count of records that matches the query.
What I'd like to see is two columns with 37,781 rows. The first column should contain the first name for each row and the second column should contain the number '37,781' for every row. Is there a way to write the query to accomplish this?
You can use a CROSS JOIN. The subquery will get the count for all firstnames
and then it will include this value in each row:
SELECT firstname, d.total
FROM BigTable
CROSS JOIN
(
SELECT COUNT(*) total
FROM BigTable
WHERE firstname LIKE 'a%'
) d
WHERE firstname LIKE 'a%';
See SQL Fiddle with Demo
You can join with a subquery:
SELECT firstname, ct
FROM BigTable
JOIN (SELECT COUNT(*) ct
FROM BigTable
WHERE firstname LIKE 'a%') x ON (1 = 1)
WHERE firstname LIKE 'a%'
I feel like this used to be the case for older versions of MySQL, but this isn't working in my tests.
But according to the manual, http://dev.mysql.com/doc/refman/5.1/en/group-by-functions.html#function_count Given that COUNT(*) is a group by function, and naturally groups all of the rows together, when a GROUP BY statement is not attached, I can only see the solution to this being either multiple statements, or a sub-query. I would suggest running the 2 queries separately, if you can, but if that isn't possible, Try:
SELECT firstname,
total
FROM BigTable,
( SELECT COUNT(*) AS total
FROM BigTable ) AS dummy
WHERE firstname LIKE 'a%';