我想与滚动“连接”长按，这样用户就不必松开屏幕开始滚动。
我有姿态探测器实现...
final GestureDetector gestureDetector = new GestureDetector(new GestureDetector.SimpleOnGestureListener() {
public void onLongPress(MotionEvent e) {
// action 1
}
public boolean onScroll(MotionEvent event1, MotionEvent event2, float velocityX, float velocityY) {
// action 2
}
}
public boolean onTouchEvent(MotionEvent event) {
return gestureDetector.onTouchEvent(event);
}
但现在动作1和动作2，用户之间不得不释放屏幕...我如何连接这个动作不释放屏幕？
我不认为一个GestureDetector会做你想要什么，你就越有可能将不得不自己做。 我不知道你当前的设置，下面是一个一类OnToucListener绑在ScrollView ，将采取在考虑这两个事件：
public class ScrollTouchTest extends Activity {
private final int LONG_PRESS_TIMEOUT = ViewConfiguration
.getLongPressTimeout();
private Handler mHandler = new Handler();
private boolean mIsLongPress = false;
private Runnable longPress = new Runnable() {
@Override
public void run() {
if (mIsLongPress) {
actionOne();
mIsLongPress = false;
}
}
};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.views_scrolltouchtest);
findViewById(R.id.scrollView1).setOnTouchListener(
new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
final int action = event.getAction();
switch (action) {
case MotionEvent.ACTION_DOWN:
mIsLongPress = true;
mHandler.postDelayed(longPress, LONG_PRESS_TIMEOUT);
break;
case MotionEvent.ACTION_MOVE:
actionTwo(event.getX(), event.getY());
break;
case MotionEvent.ACTION_CANCEL:
case MotionEvent.ACTION_UP:
mIsLongPress = false;
mHandler.removeCallbacks(longPress);
break;
}
return false;
}
});
}
private void actionOne() {
Log.e("XXX", "Long press!!!");
}
private void actionTwo(float f, float g) {
Log.e("XXX", "Scrolling for X : " + f + " Y : " + g);
}
}
