只做一次,关键是保持和释放,并抑制重复时(do something once the key is

2019-06-26 23:46发布

我需要检查当用户按下一个键并释放。 如果某个键时,我会做一些一次。

我用按键来获得我想要关联与动作的按钮。 我还用旗语来克服这个问题,但它看起来疯狂

我的代码:`

InputMap inputMap = jPanel1.getInputMap();
KeyStroke keyPressed = KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false);
KeyStroke keyReleased = KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true);
//------------------------------------------
jPanel1.getActionMap().put("_1000Press", _1000Press);
inputMap.put(keyPressed, "_1000Press");
jPanel1.getActionMap().put("_1000Release", _1000Release);
inputMap.put(keyReleased, "_1000Release");
public Action _1000Press = new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {
        if(!one){
            // do some thing
            one = true;
            System.out.println(one);
        }
    }
};
public Action _1000Release = new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {
        one = false;
        System.out.println(one);
    }
};

`

当我按“1”键不放,它打印:假的真假真假真

提前致谢。

Answer 1:

这对我来说工作正常

InputMap im = getInputMap();
ActionMap am = getActionMap();

im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false), "Press");
im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true), "Release");

am.put("Press", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        if (!pressed) {

            pressed = true;
            System.out.println("press");

        }

    }

});

am.put("Release", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        if (pressed) {

            pressed = false;
            System.out.println("release");

        }

    }

});

只是,以确保我这样做

am.put("Release", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        pressed = false;
        System.out.println("release");

    }

});

它仍然工作

印刷press时,我按住1,然后打印release ,当我解开密钥。 这是我唯一的输出

有完整的代码已更新

public class TestPane extends JPanel {

    private boolean pressed;

    public TestPane() {

        InputMap im = getInputMap();
        ActionMap am = getActionMap();

        im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false), "Press");
        im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true), "Release");

        am.put("Press", new AbstractAction() {

            @Override
            public void actionPerformed(ActionEvent e) {

                if (!pressed) {

                    pressed = true;
                    System.out.println("press");

                }

            }

        });

        am.put("Release", new AbstractAction() {

            @Override
            public void actionPerformed(ActionEvent e) {

                if (pressed) {

                    pressed = false;
                    System.out.println("release");

                }

            }

        });

    }

}


Answer 2:

我不相信你可以在Linux中需要什么,因为操作系统不断发出按下/释放信号到JVM。

看到

  • 如何制止重复的keyPressed()/的keyReleased()在Swing事件
  • 如何知道用户何时真正发布Java中的一个关键?


文章来源: do something once the key is held and repeat when its released and repressed