使用QAbstractTableModel在PyQt的编辑表(Edit table in pyqt

我想在PyQt的创建一个可编辑的表格。下面是只显示该表的代码：

import sys
from PyQt4 import QtGui, QtCore
from PyQt4.QtCore import *
from PyQt4.QtGui import *

# données à représenter
my_array = [['00','01','02'],
            ['10','11','12'],
            ['20','21','22']]

def main():
    app = QApplication(sys.argv)
    w = MyWindow()
    w.show()
    sys.exit(app.exec_())

# création de la vue et du conteneur
class MyWindow(QWidget):
    def __init__(self, *args):
        QWidget.__init__(self, *args)

        tablemodel = MyTableModel(my_array, self)
        tableview = QTableView()
        tableview.setModel(tablemodel)

        layout = QVBoxLayout(self)
        layout.addWidget(tableview)
        self.setLayout(layout)

# création du modèle
class MyTableModel(QAbstractTableModel):
    def __init__(self, datain, parent = None, *args):
        QAbstractTableModel.__init__(self, parent, *args)
        self.arraydata = datain

    def rowCount(self, parent):
        return len(self.arraydata)

    def columnCount(self, parent):
        return len(self.arraydata[0])

    def data(self, index, role):
        if not index.isValid():
            return None
        elif role != Qt.DisplayRole:
            return None
        return (self.arraydata[index.row()][index.column()])

    """
    def setData(self, index, value):
        self.arraydata[index.row()][index.column()] = value
        return True
    def flags(self, index):
        return Qt.ItemIsEditable
    """    

if __name__ == "__main__":
    main()

如果我实现该方法setData和flags ，所有的项目甚至没有选择......是什么力量让THA表编辑解决？谢谢

Answer 1:

我刚刚找到了解决办法，在方法需要返回值标志QtCore.Qt.ItemIsEditable | QtCore.Qt.ItemIsEnabled | QtCore.Qt.ItemIsSelectable QtCore.Qt.ItemIsEditable | QtCore.Qt.ItemIsEnabled | QtCore.Qt.ItemIsSelectable

Answer 2:

OR Override
Qt::ItemFlags MyTableView::flags(const QModelIndex& index) const
{
    Qt::ItemFlags flags = QAbstractTableModel::flags(index);
    flags |= Qt::ItemIsEditable;
    return flags;
}